The intNums array is declared as follows: Dim intNums() As Integer = {10, 5, 7, 2}. Which of the following blocks of code correctly calculates the average value stored in the array? The intTotal variable contains the number 0 before the loop is processed. a. For Each intX As Integer In intNums intTotal += intX Next intX dblAvg = intTotal / intNums.Length b. For Each intX As Integer In intNums intTotal += intNums(intX) Next intX dblAvg = intTotal / intX c. For Each intX As Integer In intNums intTotal += intNums(intX) intX += 1 Next intX dblAvg = intTotal / intX d. None of the above.

The intNums array is declared as follows: Dim intNums() As Integer = {10, 5, 7, 2}. Which of the following blocks of code correctly calculates the average value stored in the array? The intTotal variable contains the number 0 before the loop is processed. a. For Each intX As Integer In intNums intTotal += intX Next intX dblAvg = intTotal / intNums.Length b. For Each intX As Integer In intNums intTotal += intNums(intX) Next intX dblAvg = intTotal / intX c. For Each intX As Integer In intNums intTotal += intNums(intX) intX += 1 Next intX dblAvg = intTotal / intX d. None of the above.

Programming with Microsoft Visual Basic 2017

8th Edition

ISBN:9781337102124

Author:Diane Zak

Publisher:Diane Zak

Chapter8: Arrays

Section: Chapter Questions

Problem 10RQ

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The intNums array is declared as follows: Dim intNums() As Integer = {10, 5, 7, 2}. Which of the following blocks of code correctly calculates the average value stored in the array? The intTotal, intSub, and dblAvg variables contain the number 0 before the loop is processed. a. Do While intSub < 4 intNums(intSub) = intTotal + intTotal intSub += 1 Loop dblAvg = intTotal / intSub b. Do While intSub < 4 intTotal += intNums(intSub) intSub = intSub + 1 Loop dblAvg = intTotal / intSub c. Do While intSub < 4 intTotal += intNums(intSub) intSub += 1 Loop dblAvg = intTotal / intSub – 1 d. Do While intSub < 4 intTotal = intTotal + intNums(intSub) intSub = intSub + 1 Loop dblAvg = intTotal / (intSub – 1)
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