The joint PDF of two jointly continuous random variables X and Y is S(x2 +y?) for 0 < x < 1 and 0 < y < 1, fx,y(x, y) : otherwise. c = 3/2. E(Y) = 5/8. 3(2X? + 1) 4(3X2 + 1) Show that E(Y|X) =

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A: Hello! As you have posted more than 3 sub parts, we are answering the first 3 sub-parts.  In case…

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A: Answer is 3/2

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