QUESTION 9The label on a tank of gas of unknown origin had been lost. To determine its identity (molecular weight) a certain volume of it took 121.3 seconds to effuse through a porous partition. Under identical conditions C3H 8 effused through the hole in 64.95 seconds. What is the molar mass of the unknown gas? Remember that effusion rate and time are inversely proportional to each other. Key Concept:Kinetic theory of gase: rate of effusion. Strategy: Rate of effusion, u = k/M 1/2 where k is a constant.

Given : Time required by unknown gas to effuse = 121.3 s And the time required by C3H8 to effuse…

Answered: The label on a tank of gas of unknown…

Chemistry

9th Edition

ISBN:9781133611097

Author:Steven S. Zumdahl

Publisher:Steven S. Zumdahl

Chapter5: Gases

Section: Chapter Questions

Problem 64E

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QUESTION 9

The label on a tank of gas of unknown origin had been lost. To determine its identity (molecular weight) a certain volume of it took 121.3 seconds to effuse through a porous partition. Under identical conditions C₃H ₈ effused through the hole in 64.95 seconds. What is the molar mass of the unknown gas? Remember that effusion rate and time are inversely proportional to each other.

Key Concept:Kinetic theory of gase: rate of effusion.
Strategy: Rate of effusion, u = k/M ^1/2 where k is a constant.

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