Question help The magnitude of the electric field at a certainpoint in space is 2.2 x 106 . If a charge of 6.5µC is place at that point, what magnitude of theforce will the charge experience? Round youranswer to the nearest tenth of a Newton. Formulas:kqE == electric field (N/C)charge (Coulomb, C)= distance (meters, m)force (Newtons, N)= current (Amperes, A)time (seconds, s)VF = Eq%3Dkq 92F =rvoltage (volts, V)R =resistance (Ohms, 2)V = RIRquivalent = R, +R, + R, (series)energy (Joules, J)fE= frequency (1/s = Hertz, Hz)= wavelength (meters, m)= pressure (Pascals, Pa)= volume (m³)= temperature (Kelvin, K)= number of moles (mol)111(parallel)%3DR R, R R,hcE= hf =VPV = nRTnIf the number of molesis constant (n1 = n2), thenPV PVrTTrConversions:1 inch = 2.54 cm1 m3 = 1000 L1 atm = 1.013 × 105 PaKelvin = 273 + CelsiusSTP = Standard Temperatur & Pressure (0°C and 1 atm)Constants:Molar Masses:N.m2Nitrogen, N:14-molk =9.0x10°e =1.60x101 CAir: 29 8molR=8.314-mol- Kh = 6.626x1034 J.sC = 3.0x10 Dm

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The magnitude of the electric field at a certain point in space is 2.2 x 10° . If a charge of 6.5 µC is place at that point, what magnitude of the force will the charge experience? Round your answer to the nearest tenth of a Newton.

The magnitude of the electric field at a certain point in space is 2.2 x 10° . If a charge of 6.5 µC is place at that point, what magnitude of the force will the charge experience? Round your answer to the nearest tenth of a Newton.

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter24: Electric Fields

Section24.2: Special Case: Electric Field Of A Charged Sphere

Problem 24.2CE: What is the magnitude of the electric field due to a charged particle at its exact location (r = 0)?

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Question

Question help

The magnitude of the electric field at a certain
point in space is 2.2 x 106 . If a charge of 6.5
µC is place at that point, what magnitude of the
force will the charge experience? Round your
answer to the nearest tenth of a Newton.

Formulas:
kq
E =
= electric field (N/C)
charge (Coulomb, C)
= distance (meters, m)
force (Newtons, N)
= current (Amperes, A)
time (seconds, s)
V
F = Eq
%3D
kq 92
F =
r
voltage (volts, V)
R =resistance (Ohms, 2)
V = RI
Rquivalent = R, +R, + R, (series)
energy (Joules, J)
f
E
= frequency (1/s = Hertz, Hz)
= wavelength (meters, m)
= pressure (Pascals, Pa)
= volume (m³)
= temperature (Kelvin, K)
= number of moles (mol)
1
1
1
(parallel)
%3D
R R, R R,
hc
E= hf =
V
PV = nRT
n
If the number of moles
is constant (n1 = n2), then
PV PVr
T
Tr
Conversions:
1 inch = 2.54 cm
1 m3 = 1000 L
1 atm = 1.013 × 105 Pa
Kelvin = 273 + Celsius
STP = Standard Temperatur & Pressure (0°C and 1 atm)
Constants:
Molar Masses:
N.m2
Nitrogen, N:14-
mol
k =9.0x10°
e =1.60x101 C
Air: 29 8
mol
R=8.314-
mol- K
h = 6.626x1034 J.s
C = 3.0x10 Dm

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