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The manager of a computer software company wishes to study the number of hours per week senior executives by type of industryspend at their desktop computers. The manager selected a sample of five executives from each of three industries. At the 0.05significance level, can she conclude there is a difference in the mean number of hours spent per week by industry?Banking Retail Insurance1210Rectangular Snip1081061288101010Click here for the Excel Data File1. State the null hypothesis.HO 1u3H1 Treatment meansall the same. 2. What is the decision rule? (Round your answer to 2 decimal places.)F 0.05>Recta3. Complete the ANOVA table. (Round your SS, MS, and Fvalues to 2 decimal places.)Analysis of VarianceSourceSSdfMSFTreatmentsError4. State your decision regarding the null hypothesis.Decision:Но

Question
The manager of a computer software company wishes to study the number of hours per week senior executives by type of industry
spend at their desktop computers. The manager selected a sample of five executives from each of three industries. At the 0.05
significance level, can she conclude there is a difference in the mean number of hours spent per week by industry?
Banking Retail Insurance
12
10
Rectangular Snip
10
8
10
6
12
8
8
10
10
10
Click here for the Excel Data File
1. State the null hypothesis.
HO 1
u3
H1 Treatment means
all the same.
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The manager of a computer software company wishes to study the number of hours per week senior executives by type of industry spend at their desktop computers. The manager selected a sample of five executives from each of three industries. At the 0.05 significance level, can she conclude there is a difference in the mean number of hours spent per week by industry? Banking Retail Insurance 12 10 Rectangular Snip 10 8 10 6 12 8 8 10 10 10 Click here for the Excel Data File 1. State the null hypothesis. HO 1 u3 H1 Treatment means all the same.

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2. What is the decision rule? (Round your answer to 2 decimal places.)
F 0.05>
Recta
3. Complete the ANOVA table. (Round your SS, MS, and Fvalues to 2 decimal places.)
Analysis of Variance
Source
SS
df
MS
F
Treatments
Error
4. State your decision regarding the null hypothesis.
Decision:
Но
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2. What is the decision rule? (Round your answer to 2 decimal places.) F 0.05> Recta 3. Complete the ANOVA table. (Round your SS, MS, and Fvalues to 2 decimal places.) Analysis of Variance Source SS df MS F Treatments Error 4. State your decision regarding the null hypothesis. Decision: Но

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check_circleAnswer
Step 1

1. According to the provided data, the null and the alternative hypotheses can be stated as:

H, Treatment means are not all the same
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H, Treatment means are not all the same

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Step 2

Parts 2, 3 and 4 are solved using Excel.

Follow the below steps:

Step 1: Enter the data in the spreadsheet.

Step 2: Go to Data>Data Analysis>Anova single factor.

Step 3: Fill all the required columns and then click ok.

Step 4: The obtained result is,

Anova: Single Factor
SUMMARY
Average Varian ce
Groups
Count
Sum
Banking
Retail
Insurance
54
10.8
1.2
8
40
2
5
42
8.4
2.8
ANOVA
Source of Variation
F crit
df
P-value
SS
MS
F
Between Groups
Within Groups
22.93333
2 11.46667 5.733333
0.01788 3.885294
24
12
2
Total
46.93333
14
n n
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Anova: Single Factor SUMMARY Average Varian ce Groups Count Sum Banking Retail Insurance 54 10.8 1.2 8 40 2 5 42 8.4 2.8 ANOVA Source of Variation F crit df P-value SS MS F Between Groups Within Groups 22.93333 2 11.46667 5.733333 0.01788 3.885294 24 12 2 Total 46.93333 14 n n

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Step 3

2. The obtained p-value is 0.02 which is less than the level of significance, 0.05. ...

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Tagged in

Math

Statistics

Hypothesis Testing

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