The mean weight for college students is 175 pounds. A sample of 30 students at a college is taken, and the mean of the sample is 180 pounds with standard deviation 20 pounds. A company wants to see if the weights of the students at the college are statistically different from the national average at the 95% confidence level. Find the p-value in the table for the table value of t closest to the calculated value of the test statistic (round to 2 decimal places).

Q: In a sample of 55 electric motors, the average efficiency (in percent) was 85 and the standard…

A: From the provided information, Sample size (n) = 55 Sample mean (x̅) = 85 Standard deviation (s) = 2…

Q: A survey of 100 retailers revealed that the mean after-tax profit was $80,000. Assuming that the…

A: Given data,n=100σ=15,000x=80,000z-value at 95% confidence is Zc=1.96

Q: The number of M&Ms in a 6 oz bag is normally distributed with a mean of 18.45 and a standard…

A:

Q: Last Wednesday, a random sample of 12 students were surveyed to find how long it takes to walk from…

A: To find a 90% confidence interval we have to use the acceptance region of a one-sample t-test. This…

Q: Wildlife conservationists studying grizzly bears in the United States found that the mean weight of…

A:

Q: Based on previous school records, the standard deviation of the height of Grade 10 students in a…

A: Confidence interval is an interval such that the probability of the unknown parameter to be included…

Q: A quality control manager wants to be sure that the standard deviation of oil containers is below a…

A: Let Xi be the amount of oil in the ith container,i=1,2,...,n.

Q: The average price of a sample of 12 bottles of diet salad dressing taken from different stores is…

A: Here given that X1 bar= 1.43, n1= 12 And standard deviation, s1= 0.09 X2 bar = 1.03, n2= 16 S2= 0.10…

Q: A survey of college students reported that in a sample of 41 male college students, the average…

A: Obtain the 99% confidence interval for the difference between men and women in the mean number of…

Q: The heights of 8 Japanese men were taken with sample mean of 155 cm (centimeters) and standard…

A:

Q: 4. A recent study of 19 students of San Rafael College showed that the mean of the distance they…

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Q: In a survey, 26 people were asked how much they spent on their child's last birthday gift. The…

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Q: According to the National Health Statistics Report, a sample of 360 one year old baby boys in the US…

A:

Q: In a random sample of nine people, the mean driving distance to work was 25 miles the sample…

A:

Q: A survey of college students reported that in a sample of 41 male college students, the average…

A: From the provided information,

Q: The admissions officer at a small college compares the scores on the Scholastic Aptitude Test (SAT)…

A: Since, the population variances are unknown the Student's t-test will be applied. The variances are…

Q: A study by the department of education of a certain state was trying to determine the mean SAT…

A: Here we need to construct a 95% confidence interval for the population mean. Since the population…

Q: Last Wednesday, a random sample of 16 students were surveyed to find how long it takes to walk from…

A: From the provided information, Sample size (n) = 16 Sample mean (x̅) = 10 minutes Sample standard…

Q: The tolerable level of a certain pollutant is 16 mg/l. A researcher takes a sample of size n=50, and…

A:

Q: A consumer magazine has conducted a simple random sample of 15 owners of a certain automobile and…

A: Obtain the 99% confidence interval for the population mean.   The 99% confidence interval for the…

Q: A random sample of 87 airline pilots had an average yearly income of $99,400 with a standard…

A: Givensample size(n)=87Mean(x)=99400standard deviation(s)=12000

Q: A community health plan wishes to estimate the mean number of visits per plan participant in a year.…

A: From the provided information, Margin of error (E) = ±1.8 Standard deviation (σ) = 2.8 The…

Q: In a sample of 90 large grade A eggs, the mean number of calories was 70 with a standard deviation…

A:

Q: How much money does the average professional football fan spend on food at a single football game?…

A: Given information- Population standard deviation, σ = $17.50 Sample size, n = 60 Sample mean, x-bar…

Q: Is the margin of error for a confidence interval for a population equivalent to the standard…

A: The margin of error for a confidence interval when population standard deviation is known, The…

Q: The secretary of administration in a master's program in business administration has observed that…

A: The confidence interval is an inference process which is used to estimate the population parameter.…

Q: It is known that the population mean for the verbal section of the SAT is 500 with a standard…

A: From the provided information, Sample size (n) = 400 Sample mean (x̅) = 511 Population standard…

Q: A marketing research company desires to know the mean consumption of milk per week among people over…

A: Given data: Sample mean  = 4.6 liters Margin of error  = 0.08 liters Confidence level = 90%…

Q: In a sample of 15 small candles, the weight is found to be 3.72 ounces with a standard deviation of…

A: It is given that,Sample mean = 3.72 ounces.Sample standard deviation, s is 0.963 ounces.The sample…

Q: Last Wednesday, a random sample of 16 students were surveyed to find how long it takes to walk from…

A:

Q: To determine the views of students on a particular campus about fraternities, an 11-point attitude…

A:

Q: A marine biologist is interested in whether the Chinook salmon, a particular species of salmon in…

A: Confidence Interval: Confidence interval is the interval estimate of the population parameter. It is…

Q: In a survey, 19 people were asked how much they spent on their child's last birthday gift. The…

A:

Q: A biology student measured the ear lengths of an SRS of 10 Mountain cottontail rabbits. The ear…

A: Given: Sample size n=10 Population standard deviation σ=0.4

Q: The monthly advertising expenditure of the company is normally distributed with a standard deviation…

A:

Q: Find the critical value, t c,  used for a 97% confidence interval for the mean with a sample size of…

A: The confidence level is, 100 (1 – α) % = 97%. Hence, (1 – α) = 0.97, and the significance level is,…

Q: Statistics ( Sampling Distributions and Estimation )

A:

Q: The Martin County Health Department needs to estimate the proportion of county residents with high…

A: Given information We have given that; a health department researcher found that 221 out of a random…

Q: The monthly advertising expenditure of the company is normally distributed with a standard deviation…

A:

Q: In order to determine the average weight of carry-on luggage by passengers in airplanes, a sample of…

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Q: A random sample of 82 customers, who visited a department store, spent an average of $71 at this…

A:

Q: in this region to be 33 pounds. What sample size would you need to in order to estimate the mean…

A:

Q: A college alumni Organization sent a survey to all recent graduates to ask their annual income. 20%…

A: Given, All recent graduates of a college were asked their annual income for a survey that was…

Q: 1. A recent study stated that if a person smoked, the average of the number of cigarettes he or she…

A: Data given Population mean μ=14, n=40, sample mean x̄=18, s=6, level of significance ɑ=0.05

Q: In a random sample of 25 ​people, the mean commute time to work was 30.3 minutes and the standard…

A: The sample mean is 30.3 and the standard deviation is 7.2.

Q: A bottled water distributor wants to estimate the amount of water contained in 1​-gallon bottles…

A: Sample mean = x̅ = 0.991 Sample size = n = 50 Population S.D = σ = 0.02 Standard Error = σ/√n…

Q: A large city newspaper periodically reports the mean cost of dinner for two people at restaurants in…

A: Determine the sample size n needed. Here, confidence level is 0.95. Use EXCEL Procedure for…

Q: The determination of copper in a seawater sample gave a mean value of 77.81 mg/L and a ndard…

A: Critical value: The confidence level is 100*(1–α)% = 95%. The critical value is obtained as 1.96…

Q: In a survey of a random sample of 49 college students, the sample mean time per week spent watching…

A: Given Sample size n=49, sample mean x̄=21, standard deviations s=6.2

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.