The method of reduction of order (Section 3.4) can also be used for the nonhomogeneous equation y/" + p(t)y' + q(t)y = g(t), provided one solution y1 of the corresponding homogeneous equation is known. Let y = v(t)y1(t). It can be shown that y satisfies (38) equation (38) if v is a solution of y1(t)u" + (2y (t) + p(t)y1(t))v' = g(t). Equation (39) is a first order linear equation for v'. Solving this equation, integrating the result, and then multiplying by y1(t) leads (39) to the general solution of the first equation. Use the method above to solve the differential equation ty" – 2ty + 2y = 14t², t > 0, y1(t) = t. - NOTE: Use c; and cz as arbitrary constants. y(t) :

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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The method of reduction of order (Section 3.4) can also be used for
the nonhomogeneous equation
y" + p(t)y/ + q(t)y = g(t),
(38)
provided one solution y1 of the corresponding homogeneous equation
is known. Let y = v(t)y1(t). It can be shown that y satisfies
equation (38) if v is a solution of
y1(t)v" + (2y%(t) + p(t)y1(t))v' = g(t).
Equation (39) is a first order linear equation for v'. Solving this
equation, integrating the result, and then multiplying by y1(t) leads
(39)
to the general solution of the first equation.
Use the method above to solve the differential equation
ty" – 2ty + 2y = 14t², t > 0, yı(t) = t.
-
NOTE: Use c; and co as arbitrary constants.
y(t) :
Transcribed Image Text:The method of reduction of order (Section 3.4) can also be used for the nonhomogeneous equation y" + p(t)y/ + q(t)y = g(t), (38) provided one solution y1 of the corresponding homogeneous equation is known. Let y = v(t)y1(t). It can be shown that y satisfies equation (38) if v is a solution of y1(t)v" + (2y%(t) + p(t)y1(t))v' = g(t). Equation (39) is a first order linear equation for v'. Solving this equation, integrating the result, and then multiplying by y1(t) leads (39) to the general solution of the first equation. Use the method above to solve the differential equation ty" – 2ty + 2y = 14t², t > 0, yı(t) = t. - NOTE: Use c; and co as arbitrary constants. y(t) :
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