The non-parametric test for determining the difference between two populations based on paired samples is 1.00 None of theseO Kruskal Wallis test Median test for randomness Mann-Whitney U test Test for randomness
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Q: True or False? A Kruskal-Wallis test is used to compare a continuous outcome in more than two…
A: Solution: Kruskal-Wallis test is a non-parametric test that is used to compare the more than two…
Q: The non-parametric test for determining the difference between two populations based on paired…
A: Given: 1) The provided test is non-parametric. 2) The test is used for determining the difference…
Q: true or false? a Kruskal-Wallis test is used to compare a continuous outcome in matched samples…
A: Solution: Kruskal-Wallis test: This is a non-parametric test that is used to compare the more than…
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A: The paired difference has the outliers.
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Q: True/false: You are more likely to make a Type I error when using a small sample than when using a…
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- The mean weight of super model winners is greater than 108 pounds. A study of 25 randomly selected super model resulted in a mean winner weight of 115 pounds. Choose the correct Null and Alternative HypothesisThis is the result of Chi Square test between 2 variables: gender and length of service. If the Null Hypothesis is stated as "There is no significant association between gender and length of service", then table above will clearly allow us to conclude that "there is no significant association between gender and length of service". A. True B. FalseAlthough the chi-square homogeneity test and the chi-square independence test use essentially the same basic procedure, the context of the two tests are quite different. Explain the difference.
- In statistical testing, based on this given below, we could use parametric (ANOVA) or non parametric (Kruskal-Wallis) for testing the hypothesis. Using normality testing -- analytically and graphically, decide wether we use an anova (normally distributed) or kruskal-wallis test (not normally distributed).In a random sample of males, it was found that 17 write with their left hands and 218 do not. In a random sample of females, it was found that 56 write with their left hands and 449 do not. Use a 0.01 significance level to test the claim that the rate of left-handeness among males is less than that among females. Complete parts (a) through (c) below. a. test the claim using the hypothesis test. Consider the first sample to be the sample of males and the second sample to be the sample of females. What are the null and alternative hypothesis for the hypothesis test? Identify the test statistic. Identify the P-value. What is the conclusion based on the hypothesis test? b. test the claim by constructing an appropitae confidence interval The 98% confidence interval is _ < (p1 - p2) < _ c. based on the results, is the rate of left handeness among males less than the rate of left handeness among females?In a random sample of males, it was found that 23 write with their left hands and 217 do not. In a random sample of females, it was found that 73 write with their left hands and 459 do not. Use a 0.01 significance level to test the claim that the rate of left-handedness among males is less than that among females. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of males and the second sample to be the sample of females. What are the null and alternative hypotheses for the hypothesis test? A. H0: p1≤p2 H1: p1≠p2 B. H0: p1≥p2 H1: p1≠p2 C. H0: p1=p2 H1: p1>p2 D. H0: p1=p2 H1: p1≠p2 E. H0: p1≠p2 H1: p1=p2 F. H0: p1=p2 H1: p1<p2 Identify the test statistic. z=enter your response here (Round to two decimal places as needed.) Identify the P-value. P-value=enter your response here (Round to three…
- In a random sample of males, it was found that 29 write with their left hands and 220 do not. In a random sample of females, it was found that 68 write with their left hands and 448 do not. Use a 0.01 significance level to test the claim that the rate of left-handedness among males is less than that among females. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of males and the second sample to be the sample of females. What are the null and alternative hypotheses for the hypothesis test? A. H0: p1≠p2 H1: p1=p2 B. H0: p1=p2 H1: p1>p2 C. H0: p1≥p2 H1: p1≠p2 D. H0: p1≤p2 H1: p1≠p2 E. H0: p1=p2 H1: p1<p2 F. H0: p1=p2 H1: p1≠p2In a random sample of males, it was found that 29 write with their left hands and 220 do not. In a random sample of females, it was found that 68 write with their left hands and 448 do not. Use a 0.01 significance level to test the claim that the rate of left-handedness among males is less than that among females. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of males and the second sample to be the sample of females. What are the null and alternative hypotheses for the hypothesis test? A. H0: p1≠p2 H1: p1=p2 B. H0: p1=p2 H1: p1>p2 C. H0: p1≥p2 H1: p1≠p2 D. H0: p1≤p2 H1: p1≠p2 E. H0: p1=p2 H1: p1<p2 Your answer is correct. F. H0: p1=p2 H1: p1≠p2 Identify the test statistic. z=?In a random sample of males, it was found that 29 write with their left hands and 221 do not. In a random sample of females, it was found that 70 write with their left hands and 459 do not. Use a 0.05 significance level to test the claim that the rate of left-handedness among males is less than that among females. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of males and the second sample to be the sample of females. What are the null and alternative hypotheses for the hypothesis test? A. H0: p1≠p2 H1: p1=p2 Your answer is not correct. B. H0: p1≥p2 H1: p1≠p2 C. H0: p1=p2 H1: p1≠p2 D. H0: p1≤p2 H1: p1≠p2 E. H0: p1=p2 H1: p1<p2 This is the correct answer. F. H0: p1=p2 H1: p1> Identify the test statistic. Identify the P-value. What is the conclusion based on the hypothesis test? The��� P-value is_____ the…
- Suppose researchers conducted a study to see if the mean body temperature for adultswas different from 98.6 degrees Fahrenheit. For this study, they took a random sampleof 25 healthy adults and found a mean body temperature of 98.2 degrees Fahrenheit forthe sample with a standard deviation of 0.6 degrees. The temperatures of the sampleparticipants were unimodal and symmetric.a. Write the null hypothesis and alternative hypothesis and define your parameter.b. Show that the necessary conditions (Randomization Condition, 10% Condition,Nearly Normal Condition) are satisfied to perform a hypothesis test. Brieflyexplain how each condition is satisfied.c. Perform the hypothesis test and find the P-value. (To show your work: Writedown which calculator you are using and what values you are entering into thecalculator.)d. Is there strong evidence that the mean body temperature is different than 98.6degrees? Briefly explain how you know.Pose a null and alternate hypothesis for a two sample t-test using variables: Male and Female, Asthma, number of injuries, or flu shot. Can any of the variables also be used to do a Chi square test or a NOVA test?In a certain school district, it was observed that 29% of the students in the elementary schools were classified as only children (no siblings). However, in the special program for talented and gifted children, 78 out of 231 children are only children. The school district administrators want to know if the proportion of only children in the special program is significantly different from the proportion for the school district. Test at the a = 0.02 level of significance. Using the approximation for for the bimomial distribution (without the continuity correction), was in the test statistic for this sample based on the sample proportion? z = 3 decimal places P-value = 4 decimal places