The number of units consumed in a year by a consumer with a yearly average load of 90 kW is ..
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Q: The number of units consumed in a year by a consumer with a yearly average load of 40 kW is ....
A: Average load = 40kw Year = 365 days 1 day = 24 hrs Total time = 365*24=8760 hrs
Q: The number of units consumed in a year by a consumer with a yearly average load of 30 kW is
A: Average load = 30 KW
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Q: The number of units consumed in a year by a consumer with a yearly average load of 80 EW is ..
A: 1 unit = 1khw-hr Total Energy consumed in 1 year = 80Kw × 1year
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A: The solution can be achieved as follows.
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Q: The number of units consumed in a year by a consumer with a yearly average load of 80 kW is
A: According to the community guidelines iam restricted to only answer the first question . For the…
Q: The number of units consumed in a year by a consumer with a yearly average load of 90 kW is
A: 1 KWH = 1 unit Given, Average load = 90 Kw
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A: Given data: P=4 HPpf=0.8
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A: The solution can be achieved as follows.
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Q: (b) Discuss electrical energy demand and its growth in Indian power sector.
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Q: f ?(?) = 160cos50? V and ?(?) = −20sin(50? − 30°)A. Calculate the instantaneous power and average…
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- One horsepower is equal to how many W?Type your question here An industrial undertaking has a connected load of 100 kW. The maximum demand is 80 kW. On an average, each machine works for 60 per cent time. Find the yearly expenditure on the electricity if the tariff is Rs 10,000 + Rs 1000 per kW of maximum demand per year + Re 1 per kWh.3 4 autof question 1f & share is presently tading at $ 66 and zarmings per share of the company were § 3, how much is the P/E Ratio? Oa 22 Ob. 15% Oc 18X
- Transform 4 dBm into milliwatts State the answer in the correct units and show all your computations24/ Determine the unit of energy if the power is measure in mega watts and the time in minutes. a. MW-minutes b. MW-hr c. KW-min d. KW-hrA company operates a 500kW overhead crane for 21days a month.the crane operates for an equivalent 6hours a day at 0.8lagging power factor. Tariff structure is as follows Energy charge- 20cents/kWh Power factor credit- 3% of energy charge for every 0.01 that exceeds 0.75 Power factor penalty- 3% of energy charge for every 0.01 that pf falls below 0.75 1.Determine monthly electricity bill based on the tariff structure. 2.What will be savings on the monthly electricity bill if power factor is improved to 0.82 lagging
- Transform 200 milliwatts into dBm state the answer in the correct units and show all your computations to receive creditA generating station has an overall efficieney of 15% and 0-75 kg of coal is bumt per kWh by the station. Determine the calorific value of coal in kilocalories per kilogram. ANSWER:176-44 kcal/kg SHOW YOUR COMPLETE SOLUTIONAssume that electricity is supplied at a price of 100Bz per unit. Calculate the electricity bill in a month of 31 days for a house having the following electrical appliances with their average daily use: One electric iron of 500W working for 0.5 hours a day. One air conditioner of 1000W working for 6 hours a day. 2 exhaust fans each of 25W and work for 1 hour a day.
- What are the watt-seconds supplied by a motor developing 3 British hp for 4 hours?An industrial undertaking has a connected load of 100 kW. The maximum demand is 80 kW. On an average, each machine works for 60 per cent time. Find the yearly expenditure on the electricity if the tariff is Rs 10,000 + Rs 1000 per kW of maximum demand per year + Re 1 per kWh.If Rout is 3kilo-ohms, find its power dissipated.