The [OH] in a 0.20M solution ofNH4OH is: (Kb for NH4OH = 1.8 x 10-5)O 3.6 x 10-6 MO 1.8 x 10-5 MO 1.89 x 10-3 MO 4.2 x 10-4 M

Given: Initial concentration of NH4OH=0.20 M Kb of NH4OH = 1.8×10-5 Let x be the dissociated amount…

Answered: The [OH] in a 0.20M solution of NH4OH…

The [OH] in a 0.20M solution of NH4OH is: (Kb for NH4OH = 1.8 x 10-5) 3.6 x 10-6 M O 1.8 x 10-5 M 1.89 x 10-3 M O 4.2 x 10-4 M

Chemistry by OpenStax (2015-05-04)

1st Edition

ISBN:9781938168390

Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser

Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser

Chapter14: Acid-base Equilibria

Section: Chapter Questions

Problem 74E: The pH of a 0.20-M solution of HP is 1.92. Determine Ka far HF from these data.

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Question

The [OH] in a 0.20M solution of
NH4OH is: (Kb for NH4OH = 1.8 x 10-5)
O 3.6 x 10-6 M
O 1.8 x 10-5 M
O 1.89 x 10-3 M
O 4.2 x 10-4 M

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