The Oscar Mayer Weinermobile is moving at 6.6 m/s when it begins to accelerate at 3.1 m/s2. To the nearest tenth of a second, how long does it take for the Weinermobile to reach a speed of 16.4 m/s?

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter2: Motion In One Dimension
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The Oscar Mayer Weinermobile is moving at 6.6 m/s when it begins to accelerate at 3.1 m/s2. To the nearest tenth of a second, how long does it take for the Weinermobile to reach a speed of 16.4 m/s?

 

Expert Solution
Step 1

Initial speed of Weinermobile is

 U = 6.6 m/s

Acceleration of the Weinermobile is

 a = 3.1 m/s²

Final speed is V = 16.4 m/s

Let time be t 

 

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