The percent composition by mass of a compound is 76.0% C, 12.8% H, and 11.2%0 At. wt. C= 12 g/mol O= 16 g /mol H= 1 g/mol What is the Empircal formula of the compound? O CGH9O O C18H180 O CGH180 O CgHgO O CGH1802
The percent composition by mass of a compound is 76.0% C, 12.8% H, and 11.2%0 At. wt. C= 12 g/mol O= 16 g /mol H= 1 g/mol What is the Empircal formula of the compound? O CGH9O O C18H180 O CGH180 O CgHgO O CGH1802
Chapter4: Molecules, Compounds, And Chemical Reactions
Section: Chapter Questions
Problem 32E: The formula mass of an unknown compound containing only C and H is 70.1 amu. What is its molecular...
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