The phosphorus in a 0.2091-g sample was precipitated as the slightly soluble (NH4)3PO4 -12M0O3. This precipitate was filtered, washed, and then redissolved in acid. Treatment of the resulting solution with an excess of Pb* resulted in the formation of 0.2922 g of PBM0O4 (367.14 g/mol). Express the results of this analysis in terms of percent P205 (141.94 g/mol). Show your solution. O A. 2.251 % B. 1.257 % O C. 5.215 % D. 2.154 %

Fundamentals Of Analytical Chemistry
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Chapter12: Gravimetric Methods Of Analysis
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Problem 12.29QAP
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The phosphorus in a 0.2091-g sample was precipitated as the slightly soluble (NH4)3PO4
12MOO3. This precipitate was filtered, washed. and then redissolved in acid. Treatment of the
resulting solution with an excess of Pb* resulted in the formation of 0.2922 g of PbMoO4
(367 14 g/mol) Express the results of this analysis in terms of percent P2O5 (141.94 g/mol)
Show your solution.
OA 2 251 %
OB 1257 %
O C 5.215 %
OD. 2.154 %
O E. 2.315%
Transcribed Image Text:The phosphorus in a 0.2091-g sample was precipitated as the slightly soluble (NH4)3PO4 12MOO3. This precipitate was filtered, washed. and then redissolved in acid. Treatment of the resulting solution with an excess of Pb* resulted in the formation of 0.2922 g of PbMoO4 (367 14 g/mol) Express the results of this analysis in terms of percent P2O5 (141.94 g/mol) Show your solution. OA 2 251 % OB 1257 % O C 5.215 % OD. 2.154 % O E. 2.315%
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