The plates of a parallel-plate capacitor have a separation of 4.28 mm, and each has an area of 16.2 cm². Each plate carries a charge of magnitude 5.35x10-8 C. The plates are in vacuum. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Properties of a parallel-plate capacitor. What is the capacitance? Express your answer with the appropriate units. C = 3.35x10-12 F Submit ✓ Correct Part B Previous Answers Set Up: C =- C € A d Solve: C = 0 = €0 V= 2.310-10 What is the potential difference between the plates? Express your answer with the appropriate units. Part C E= and V = Ed. Submit Previous Answers Request Answer 1.62x10-³ m² 4.28x10-³ m UA X Incorrect; Try Again; 5 attempts remaining Value V 3 3.35 x 10-12 F What is the magnitude of the electric field between the plates? Express your answer with the appropriate units. ? Units ?

Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter25: Capacitance And Dielectrics
Section: Chapter Questions
Problem 48CP: A parallel-plate capacitor with plates of area LW and plate separation t has the region between its...
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The plates of a parallel-plate capacitor have a separation of 4.28 mm, and each
has an area of 16.2 cm². Each plate carries a charge of magnitude 5.35x10-8 C.
The plates are in vacuum.
For related problemsolving tips and strategies, you may want to view a Video
Tutor Solution of Properties of a parallel-plate capacitor.
What is the capacitance?
Express your answer with the appropriate units.
C = 3.35x10-12 F
Submit
Correct
Set Up: C =
Part B
Previous Answers
Solve: C = €0
€0 A
d
V= 2.3107
Part C
E =
What is the potential difference between the plates?
Express your answer with the appropriate units.
C =
= €0
10
uA
Value
and V = Ed.
1.62×10-³ m²
4.28x10-³ m
Submit Previous Answers Request Answer
- 3.35 x 10-12 F
V
X Incorrect; Try Again; 5 attempts remaining
What is the magnitude of the electric field between the plates?
Express your answer with the appropriate units.
?
Units
?
Transcribed Image Text:The plates of a parallel-plate capacitor have a separation of 4.28 mm, and each has an area of 16.2 cm². Each plate carries a charge of magnitude 5.35x10-8 C. The plates are in vacuum. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Properties of a parallel-plate capacitor. What is the capacitance? Express your answer with the appropriate units. C = 3.35x10-12 F Submit Correct Set Up: C = Part B Previous Answers Solve: C = €0 €0 A d V= 2.3107 Part C E = What is the potential difference between the plates? Express your answer with the appropriate units. C = = €0 10 uA Value and V = Ed. 1.62×10-³ m² 4.28x10-³ m Submit Previous Answers Request Answer - 3.35 x 10-12 F V X Incorrect; Try Again; 5 attempts remaining What is the magnitude of the electric field between the plates? Express your answer with the appropriate units. ? Units ?
Expert Solution
Step 1

Given

Separation between the each plate is given as d=4.28 mm=4.28×10-3 m

Area of each plate is A=16.2 cm2=16.2×10-4 m2

Magnitude of charge on each plate of the capacitor is Q=5.35×10-8 C

 

 

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