The position of a particle is defined by s=6t²-8+40cosπ where s and t are expressed in inches and seconds respectively. Determine the position,velocity and acceleration when t=6 seconds
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- The equation of motion of a particle is s = 8t2 + 3t – 10, where s is in meters and t in seconds. Find the velocity at the point of origin (in m/s).0The equation below gives the velocity of a particle that moves along a straight line. Find the particle's position at x = π seconds. Express your answer to the nearest whole number and in m/s². v=1/sin(t)+1In the given figure, calculate the value of h if the moment of inertia of the plane region under the u-axis is 120x10^9 mm^4 and I, is equal to 14x10^3 mm, The area is given by 90x10^3 mm^4, Answer in a whole number.
- SUBJECT: Dynamics of Rigid Bodies. PLEASE BOX THE FINAL ANSWER The motion of a particle is defined by the relation x = 8t^3 – 8 + 30 sin πt, where x and t are expressed inmillimeters and seconds, respectively. Determine the position, the velocity, and the acceleration of the particlewhen t = 5 s.The velocity of a particle moving along the x-axis is given by the function v (t) = 2t^3 + 15 for t > 0. Find the total distance traveled by the particle from t=2 to t=4.A particle moves that is defined by the parametric equations given below (where x and y are in meters, and t is in seconds). Compute the radial component of the velocity (m/s) at t = 2 seconds.
- Show the complete solution and the necessary graphs/diagrams. Use 2 decimal places in the final answer. A particle moves that is defined by the parametric equations given below (where x and y are in meters, and t is in seconds). Compute the angular velocity (rad/s) at t = 2 seconds.a. Set up the equations of motion that is required to solve the problem. b. Determine the magnitude of W in the figure so that the 200 lb. body will have an acceleration up the plane of 4.025 fps^2calculate, in regard to the center of area, 1. Moment of inertia Ixx 2. Polar moment of inertia J0 3.By rotating the area around the y axis a volume is created , calculate this volume
- A particle travels counterclockwise around a circle of 36m radius so that the distance from a fixed point 0 on the right end of a horizontal diameter is given by s=20t + 2t^2 where s is in meters and t is in seconds. Compute the rectangular components of acceleration at the end of 2 seconds.Determine the change in mass moment of inertia of an object that could be modeled as a point mass m when its distance from a center of rotation is doubled.1.The location of a certain particle that is only limited to move along a linear direction is given by S = 2t^3 – 24t + 6, such that the unit of s is in meters from an acceptable origin and t is measured in seconds. Solve for the following: -The time needed for that certain particle to attain a velocity of 72 m/s from rest when t = 0. -The acceleration of the particle when it reaches V = 30 m/s -Net displacement in meters from t = 1 second to t = 4 seconds