The position of an object as a function of time is given by x = bt2 - ct, where b = 2.0 m/s2 and c = 6.7 m/s, and x and t are in SI units. What is the instantaneous velocity of the object when t = 2.3?

The position of an object as a function of time is given by x = bt2 - ct, where b = 2.0 m/s2 and c = 6.7 m/s, and x and t are in SI units. What is the instantaneous velocity of the object when t = 2.3?

Name: The position of an object as a function of time is given by x = bt2 -
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: The position of an object as a function of time is given by x = bt2 - ct, where b = 2.0 m/s2 and c = 6.7 m/s, and x and t are in SI units. What is the instantaneous velocity of the object when t = 2.3?

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The position of a particle moving along the x axis varies in time according to the expression x = 3t2, where x is in meters and t is in seconds. Evaluate its position (a) at t = 3.00 s and (b) at 3.00 s + t. (c) Evaluate the limit of x/t as t approaches zero to find the velocity at t = 3.00 s.
The position of an object is given by x = at3 - bt2 + ct,where a = 4.1 m/s3, b = 2.2 m/s2, c = 1.7 m/s, and x and t are in SI units. What is the instantaneous acceleration of the object when t = 3.5 s?
An object is moving along the x-axis. At t = 0 it is at x = 0. Its x-component of velocity vx as a function of time is given by vx(t)=αt−βt3, where α=α= 7.6 m/s2 and β= 4.4 m/s4. At what nonzero time tt is the object again at xx = 0?
During the time interval 0 < t < 1, the velocity of an object as a function of time is v = 5 + 3t^2 + 2t^3. Knowing that the object follows a rectilinear trajectory, What is the correct expression for the acceleration?
Using SI base units, a particle’s position as a function of time is given by x(t)=(7t3+4t2+6) m. (a) At what time will the particle’s acceleration be zero? (b) Find the speed of the particle at that time.
An object is moving along the x-axis. At t = 0 it is at x = 0. Its x-component of velocity Vx as a function of time is given by: Vx(t) = at - Bt3, where a = 6.8 m/s2 and B = 4.0 m/s4 I. At what nonzero time t is the object again at x = 0? (Express your answer with the appropriate units.) II. At t = 1.8 s, what is the x-component of the velocity of the object? (Express your answer with the appropriate units.) III. At t = 1.8 s, what is the x-component of the acceleration of the object? (Express your answer with the appropriate units.)
An object has an acceleration defined by the equation a=5t+4 (m/s^2) where "t" is in seconds. The initial velocity of the object is -10 m/s and started at a position s = 40m. 1. What is the initial magnitude of the acceleration of the object? Express your answer in unit of m/s^2 2. What is the velocity of the object after 4s? Express your answer in unit of m/s. 3. What is the position of the object after 4s? Express your answer in unit of m.
An object's position in the x-direction as a function of time is given by the expression; x(t) = 5t2 + 2t where are quantities have proper SI Units. What is the object's average velocity in the x-direction between the times t = 1.3 s and t = 2.28 s.
The position of a particle moving along the x axis depends on the time according to the equation x = ct4 - bt6, where x is in meters and t in seconds. Let c and b have numerical values 2.7 m/s4 and 1.4 m/s6, respectively. From t = 0.0 s to t = 1.7 s, (a) what is the displacement of the particle? Find its velocity at times (b) 1.0 s, (c) 2.0 s, (d) 3.0 s, and (e) 4.0 s. Find its acceleration at (f) 1.0 s, (g) 2.0 s, (h) 3.0 s, and (i) 4.0 s.
The position of a particle moving in one dimension along the x axis is given by x(t) =5.5 + 7.8t + 2.1t2, where t is measured in seconds and x in meters. What is the velocity of the particle as function of time? What is the acceleration as a function of time?
Between t = 0 and t = t0, a rocket moves straight upward with an acceleration given by a(t) = A − Bt1 /2 , where A and B are constants. (a) If x is in meters and t is in seconds, what are the units of A and B? (b) If the rocket starts from rest, how does the velocity vary between t = 0 and t = t0? (c) If its initial position is zero, what is the rocket’s position as a function of time during this same time interval?
The position of a particle moving along the x axis depends on the time according to the equation x = ct4 - bt5, where x is in meters and t in seconds. Let c and b have numerical values 2.0 m/s4 and 1.6 m/s5, respectively. From t = 0.0 s to t = 1.5 s, what is the displacement of the particle?