Answered: the velocity of an object is given by v…

Name: the velocity of an object is given by v = 3.6t +2.6 (m / s). determine
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: the velocity of an object is given by v = 3.6t +2.6 (m / s). determine the displacement (in meters for the time interval t1 = 2.2s and t2 = 5.1s The initial position x0 = 0

Science

Physics

the velocity of an object is given by v = 3.6t +2.6 (m / s). determine the displacement (in meters for the time interval t1 = 2.2s and t2 = 5.1s The initial position x0 = 0

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 5CQ

See similar textbooks

Similar questions

The position of a particle moving along the x axis varies in time according to the expression x = 3t2, where x is in meters and t is in seconds. Evaluate its position (a) at t = 3.00 s and (b) at 3.00 s + t. (c) Evaluate the limit of x/t as t approaches zero to find the velocity at t = 3.00 s.
During the time interval 0 < t < 1, the velocity of an object as a function of time is v = 5 + 3t^2 + 2t^3. Knowing that the object follows a rectilinear trajectory, What is the correct expression for the acceleration?
The velocity of a particle at any time t moving along an x-axis is given by the following equation: v = 3t^2 - 8t + 3 where v is in m/s. At t = 0, x = 0. Determine the following:(a) the particle's displacement between t = 0 and t = 4 s (b) the average velocity for the time interval t =0 to t = 4 s (c) the acceleration when t =3 s (d) the instantaneous velovity at t = 4 s (e) what is the initial direction of motion of the particle?
The position of a particle in m is given by the expression x(t) = 2.50 t3 - 1.40, where t is in seconds. Find its velocity at t = 2.00 s.
A graph of position vs. time for a certain particle moving along the x-axis is shown. Find the average velocity in the time intervals from a) 0 to 2.00 s, b) 0 to 4.00 s, c) 2.00 s to 4.00 s, d) 4.00 to 7.00 s, and e) 0 to 8.00 s.
The table shows the position of a cyclist. t (seconds) 0 1 2 3 4 5 s (meters) 0 1.5 4.8 10.8 17.7 24.1 (a) Find the average velocity for each time period. (i) [1, 3] m/s(ii) [2, 3] m/s(iii) [3, 5] m/s(iv) [3, 4] m/s (b) Estimate the instantaneous velocity when t = 3. m/s
The position of an object as a function of time is given by x = bt2 - ct, where b = 2.0 m/s2 and c = 6.7 m/s, and x and t are in SI units. What is the instantaneous velocity of the object when t = 2.3?
Suppose an object starts at time t=0s at a position defined as x=0m. At t=0.5s, the object is at x=1.5m, and at t=1.0s, the object is at x=2.0m. What is the average velocity for the first interval (approximated at t=0.25s) and for the second interval (approximated at t=0.75s)? What is the average acceleration of the object?
A graph of position vs. time for a certain particle moving along the x-axis is shown. Find the average velocity in the time intervals from d) 4.00 to 7.00 s, and e) 0 to 8.00 s.
Given the following acceleration function of an object moving along a line, find the position function with the given initial velocity and position. a(t) = 2 + 3 sin t; ν(0) = 1, s(0) = 10
A particle moves according to the equation v(t) = 2t^3 + 10t^2 - 5 , where v is in meters per second and t is in seconds. (a) Find the average acceleration for the time interval from 2.00 s to 3.00 s. (b)Find the instantaneous acceleration at t=2.00 s and at t=3.00 s.
In 3.2 s, a particle moving with constant acceleration along the x axis goes from x = 31 m to x = 51 m. The velocity at the end of this time interval is 12 m/s. What is the acceleration of the particle?