The probe in our telomere experiment was labeled with digoxigenin. What are the advantages of using digoxigenin as the reporter group for labeling DNA probes? Circle all correct answers. a. Digoxigenin-labeled probes are very stable. b. The Digoxigenin reporter group does not change the structure of DNA molecules. c. Digoxigenin is a small molecule with high antigenicity. Therefore, the preparation of antibodies is very efficient. d. Digoxigenin is a toxic molecule and is difficult to dispose of. e. DIG probes are about 10 x more sensitive than radioactive probes. f. All of the above

The probe in our telomere experiment was labeled with digoxigenin. What are the advantages of using digoxigenin as the reporter group for labeling DNA probes? Circle all correct answers. a. Digoxigenin-labeled probes are very stable. b. The Digoxigenin reporter group does not change the structure of DNA molecules. c. Digoxigenin is a small molecule with high antigenicity. Therefore, the preparation of antibodies is very efficient. d. Digoxigenin is a toxic molecule and is difficult to dispose of. e. DIG probes are about 10 x more sensitive than radioactive probes. f. All of the above

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter13: An Introduction To Genetic Technology

Section: Chapter Questions

Problem 20QP: Analyzing Cloned Sequences A base change (A to T) is the mutational event that created the mutant...

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Streptococcus pneumoniae cells of genotype str s mtl - are transformed by donor DNA of genotype strr mtl+ and (in a separate experiment) by a mixture of two DNAs with genotypes strr mtl - and str s mtl+. The accompanying table shows the results.a. What does the first row of the table tell you? Why? b. What does the second row of the table tell you? Why?
You can carry out matings between an Hfr and F strain by mixing the two cell types in a small patch on a plate and then replica plating to selective medium. This methodology was used to screen hundreds of different cells for a recombination-deficient recA - mutant. Why is this an assay for RecA function? Would you be screening for a recA mutation in the F or Hfr strain using this protocol? Explain.
Explain the process of how X-gal screening works with pUC19, you may build a model with boxes and arrows. 2. You are utilizing BamHI (GGATCC) restriction site and HindIII (AAGCTT) restriction site. Within pUC19, BamHI is at position 263, while HindIII is at position 233. (Hint: position is like coordinate on a map). If you manage to insert GTF2H5 in pUC19 vector, what are the sizes of fragments if you digest the pUC19-GTF2H5 (this is after insertion) with the following restriction enzyme combination after gel electrophoresis: BamHI and HindIII There is an NdeI site right in the middle of the GTF2H5 that has been inserted in pUC19, what would be the fragment sizes, if you digest with BamHI and NdeI. HindIII and NdeI BamHI, HindIII, and NdeI. 3. Design an experiment to confirm the presence of insert GTF2H5 in pUC19 vector using the following method (besides restriction analysis above), assuming that you know the sequence of GTF2H5: Southern Blot Polymerase Chain Reaction
T. Miyake and M. Demerec examined proline-requiring mutations in the bacterium Salmonella typhimurium (). On the basis of complementation testing, they found four proline auxotrophs: proA, proB, proC, and proD. To determine whether proA, proB, proC, and proD loci were located close together on the bacterial chromosome, they conducted a transduction experiment. Bacterial strains that were proC+ and had mutations at proA, proB, or proD were used as donors. The donors were infected with bacteriophages, and progeny phages were allowed to infect recipient bacteria with genotype proC− proA+ proB+ proD+. The recipient bacteria werethen plated on a selective medium that allowed only proC+ bacteria to grow. After this, the proC+ transductants were plated on selective media to reveal their genotypes at the other three pro loci. The following results were obtained: Q.Which genotypes represent single transductants and which represent cotransductants?
T. Miyake and M. Demerec examined proline-requiring mutations in the bacterium Salmonella typhimurium (). On the basis of complementation testing, they found four proline auxotrophs: proA, proB, proC, and proD. To determine whether proA, proB, proC, and proD loci were located close together on the bacterial chromosome, they conducted a transduction experiment. Bacterial strains that were proC+ and had mutations at proA, proB, or proD were used as donors. The donors were infected with bacteriophages, and progeny phages were allowed to infect recipient bacteria with genotype proC− proA+ proB+ proD+. The recipient bacteria werethen plated on a selective medium that allowed only proC+ bacteria to grow. After this, the proC+ transductants were plated on selective media to reveal their genotypes at the other three pro loci. The following results were obtained: Q.Is there evidence that proA, proB, and proD are located close to proC? Explain your answer.
T. Miyake and M. Demerec examined proline-requiring mutations in the bacterium Salmonella typhimurium (). On the basis of complementation testing, they found four proline auxotrophs: proA, proB, proC, and proD. To determine whether proA, proB, proC, and proD loci were located close together on the bacterial chromosome, they conducted a transduction experiment. Bacterial strains that were proC+ and had mutations at proA, proB, or proD were used as donors. The donors were infected with bacteriophages, and progeny phages were allowed to infect recipient bacteria with genotype proC− proA+ proB+ proD+. The recipient bacteria werethen plated on a selective medium that allowed only proC+ bacteria to grow. After this, the proC+ transductants were plated on selective media to reveal their genotypes at the other three pro loci. The following results were obtained: Q.Why are there no proC− genotypes among the transductants?
Regarding the production of recombinant monoclonal antibodies, it is CORRECT to state that: * (JUST ONE STATEMENT IS CORRECT) (A) Chimeric and humanized antibodies differ in relation to the percentage of sequence of the constant chain of molecules from the human genome (B) Chimeric antibodies are industrially produced by joining purified protein fragments of the Fab fraction of murine antibodies and the constant portion of human antibodies. (C) When using cells dependent on the DHF amplification system, we must use a vector containing the coding information of the light and heavy chains and another vector that contains the coding sequence of the enzyme dihydrofolate reductase (D)The industrial purification of monoclonal antibodies should preferably use an initial step based on the use of affinity columns, which will bind the antibodies by the Fc fraction (E) The use of amplification systems such as GS and DHFR has as main objective to make the production of monoclonal antibodies…
If you use the pUC18 vector to clone in the MCS region, predict the following: a) Do bacteria that are blue in color have a cloned insert? b)Do bacteria that are white in color have a cloned insert? c) If you were to grow these cells on Chloramphenicol (an antibiotic), would the bacteria with the pUC plasmid grow? Why or Why not?
Suggest how the researchers could have altered their targeting construct, to ensure that all of the neomycin resistant transformants would have generated the expected PCR product with the A/B primer pair.
After mutagenesis of wild type Vibrio fisheri, you isolate two different mutant strains (A and B) that, unlike the wild type cells, fail to luminesce when grown to high density in a flask with appropriate medium. Curiously, however, when you inoculate both mutant strains in the same flask, you observe that the mixed (A+B) culture begins to emit light after growing dense. a) What gene/functions are likely affected in each of the two mutants? b) How does this explain their phenotypes?
Draw and explain how the recombinant DNA molecules can be produced in a pUC19 vector using a linear DNA (dummy) at Pst1 5'_CTGCA/G_3' restriction site?
during bacterial transformation, DNA that enters acell is not an intact chromosome; instead it consists ofrandomly generated fragments of chromosomal DNA.In a transformation where the donor DNA was from abacterial strain that was a+ b+ c+ and the recipient wasa b c, 55% of the cells that became a+ were also transformed to c+. But only 2% of the a+ cells were b+. Isgene b or c closer to gene a?