The protons in a nucleus are approximately 2 x 10-15 m apart. Consider thecase where the protons are a distance d = 1.85 × 10¬15 m apart. Calculatethe magnitude of the electric force (in N) between two protons at thisdistance.NTwo charged particles, q, and q2, are located on the x-axis, with q, at theorigin and q, initially at x, = 13.8 mm. In this configuration, q, exerts a repulsiveforce of 2.62 µN on qɔ. Particle q, is then moved to x, = 17.4 mm. What is theforce (magnitude and direction) that q, exerts on q, at this new location?(Give the magnitude in µN.)magnitudedirectionThree point charges are arranged as shown in the figure below. Find themagnitude and direction of the electric force on the particle q = 4.78 nc at theorigin. (Let r,2 = 0.270 m.)magnitudedirection° counterclockwise from the +x axis6.00 nC0.100 m-3.00 nCThree charged particles are located at the corners of an equilateral triangleas shown in the figure below (let q = 1.60 µC, and L = 0.670 m). Calculatethe total electric force on the 7.00-µC charge.magnitudedirection° (counterclockwise from the +x axis)7.00 µC60.0°-4.00 μC Ο

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University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter5: Electric Charges And Fields

Section: Chapter Questions

Problem 93P: A spherical water droplet of radius 25 m carries an excess 250 electrons. What vertical electric...

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