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Asked Sep 26, 2019
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The question asks for the exact value of the trigonometric function at the given real number:

 

cos19pi/6  I answered -(sqrt)3/2   but I wanted to double check this answer

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19T Find the value of cos 6 197 cos 6 12л + 7л = COS 12л 7л + = COS 6 6 =cos 2T 6 ( cos(x+ 27) cosx) =cos 6 77T cos 6 2 2

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