The rate constant for the first-order decomposition of cyclobutane, C4​ H​ 8​ ​ at 500 °C is 9.2 × 10−​ 3​ s​−1 C4H8→ 2C2H4 How long will it take for 80.0% of a sample of C4​ ​H8​ ​ to decompose

Chemistry by OpenStax (2015-05-04)
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Chapter12: Kinetics
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Problem 29E: The rate constant for the ?rst-order decomposition at 45 C of dinitrogen pentoxide, N2O5, dissolved...
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The rate constant for the first-order decomposition of cyclobutane, C4​ H​ 8​ ​ at 500 °C is 9.2 × 10−​ 3​ s​−1 C4H8→ 2C2H4
How long will it take for 80.0% of a sample of C4​ ​H8​ ​ to decompose

Expert Solution
Step 1

For the 1st order reaction, the rate constant is:

k=2.303tlogaa-x

Where,

t is the time required, a is the product formed, and (a-x) is the reactant left in reaction.

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