Question
Asked Nov 3, 2019
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The rate of a particular gas was measured and found to be 24.0 mL/min. Under the same conditions, the rate of effusion of pure methane (CH4) gas is 47.8 mL/min. What is the molar mass of the unknown gas?

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Expert Answer

Step 1

Graham`s law of diffusion: the rate of effusion of a gas is inversely proportional to the square root of the molar mass of its particles.

1
Rate of effusion a
М
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1 Rate of effusion a М

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Step 2

For two gasses:

M2
Rate
M1
Rate2
where:
Rate1 is the rate of effusion for the first gas.
(volume or number of moles per unit time)
Rate2 is the rate of effusion for the second gas.
M1 is the molar mass of gas 1
M2 is the molar mass of gas 2.
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M2 Rate M1 Rate2 where: Rate1 is the rate of effusion for the first gas. (volume or number of moles per unit time) Rate2 is the rate of effusion for the second gas. M1 is the molar mass of gas 1 M2 is the molar mass of gas 2.

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Step 3

Calculation for molar...

М2
RateCH
МсHA
Rate2
M2
47.8 mL/min
V16
24.0 mL/min
1.99 x v16 =
М, %3D (1.99 х 4)?
M2 63.36 g/mol
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М2 RateCH МсHA Rate2 M2 47.8 mL/min V16 24.0 mL/min 1.99 x v16 = М, %3D (1.99 х 4)? M2 63.36 g/mol

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