For the reaction 3 H2(g) + N2 (g) *double arrow here* 2 NH3(g) at 472 ℃, equilibrium is established when [H2] = 0.0200 M, [N2] = 0.0100 M and [NH3] = 5.37 x 10-8 M.a) Write the equilibrium constant expression for this reaction. (Use ^ for exponents)b) Calculate the equilibrium constant for this reaction.

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Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 12.34PAE: 1’he reaction in Exercise 12.33 was repeated. This time, the reaction began when only NO was...

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For the reaction 3 H₂_(g) + N_{2 (g)} *double arrow here* 2 NH₃_(g) at 472 ℃, equilibrium is established when [H₂] = 0.0200 M, [N₂] = 0.0100 M and [NH₃] = 5.37 x 10^-8 M.

a) Write the equilibrium constant expression for this reaction. (Use ^ for exponents)

b) Calculate the equilibrium constant for this reaction.

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