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The reaction PC13(g) + Cl₂(g) = PC15(g) has AH = -87.9 kJ, AS° = -170 J/K, K = 3.32 x 10 at 298 K. Which change of conditions causes this equilibrium reaction to shift in the direction of product? Doubling all pressures by halving the volume of the reaction vessel. Adding a catalyst that accelerates the reaction rates. Increasing the temperature. O Doubling the pressure by adding Ar(g).

The reaction PC13(g) + Cl₂(g) = PC15(g) has AH = -87.9 kJ, AS° = -170 J/K, K = 3.32 x 10 at 298 K. Which change of conditions causes this equilibrium reaction to shift in the direction of product? Doubling all pressures by halving the volume of the reaction vessel. Adding a catalyst that accelerates the reaction rates. Increasing the temperature. O Doubling the pressure by adding Ar(g).

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.103PAE: 12.103 Methanol, CH3OH, can be produced by the reaction of CO with H2, with the liberation of heat....
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The reaction PC13(g) + Cl₂(g) = PC15(g) has AH = -87.9 kJ, AS° = -170 J/K, K = 3.32 × 10 at 298 K. Which change of conditions causes this equilibrium reaction to shift in the direction of product? Doubling all pressures by halving the volume of the reaction vessel. O Adding a catalyst that accelerates the reaction rates. O Increasing the temperature. Doubling the pressure by adding Ar(g).
Transcribed Image Text:The reaction PC13(g) + Cl₂(g) = PC15(g) has AH = -87.9 kJ, AS° = -170 J/K, K = 3.32 × 10 at 298 K. Which change of conditions causes this equilibrium reaction to shift in the direction of product? Doubling all pressures by halving the volume of the reaction vessel. O Adding a catalyst that accelerates the reaction rates. O Increasing the temperature. Doubling the pressure by adding Ar(g).
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