In a rollercoaster ride a passenger car at the top of the first hill is travelling at 3.5 m/s. The car then descends on rails to the bottom of the slope and then goes up the second hill where the  speed is 10 m/s. Find the difference in height between the first and second hill. (Result 4.47m

College Physics
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ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter30: Atomic Physics
Section: Chapter Questions
Problem 10CQ: Why does the energy of characteristic x rays become increasingly greater for heavier atoms?
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Hi,

I have one more follow-up question regarding a similar problem where I need to find the height:

In a rollercoaster ride a passenger car at the top of the first hill is travelling at 3.5 m/s. The car
then descends on rails to the bottom of the slope and then goes up the second hill where the 
speed is 10 m/s. Find the difference in height between the first and second hill. (Result 4.47m)

 

Attached is the formula I tried to use, however, I get a different result so I am definitely doing something wrong. Online I didn't find a similar problem so I am asking here as a last chance. Can you help?

mghat m
2
/mitmghy = 1 mvetmghe
-
27
2
tvi+ghe = fuz + ghz
ghat ghetupituz
the the = tuit
यू
= + V ₂² ²
४
FOOD
Transcribed Image Text:mghat m 2 /mitmghy = 1 mvetmghe - 27 2 tvi+ghe = fuz + ghz ghat ghetupituz the the = tuit यू = + V ₂² ² ४ FOOD
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The reason why I used 2g instead than g is that I have to cancel  2 "g" from the left side. Meaning I had to add 1/2g on the right side. Why are you instead adding only 1/g? Sorry, sometimes I get lost in the simple steps. 

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