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The roots of the characteristic equation of a linear second-order differential equation are -3 and-2. The general solution (with arbitrary constants A and B) of the differential equation is: O y = A(-3)' + B(-2)' O y = A sin(-3t) + B cos(-2t) O y = -3eAt 2eBt O y = Ae-3t + Be 2t !!

The roots of the characteristic equation of a linear second-order differential equation are -3 and-2. The general solution (with arbitrary constants A and B) of the differential equation is: O y = A(-3)' + B(-2)' O y = A sin(-3t) + B cos(-2t) O y = -3eAt 2eBt O y = Ae-3t + Be 2t !!

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The roots of the characteristic equation of a linear second-order differential equation are -3 and -2. The general solution (with arbitrary constants A and B) of the differential equation is: O y = A(-3)' + B(-2)* O y = A sin(-3t) + B cos(-2t) O y = -3eAt 2e Bt O y = Ae 3t + Be 2t
Transcribed Image Text:The roots of the characteristic equation of a linear second-order differential equation are -3 and -2. The general solution (with arbitrary constants A and B) of the differential equation is: O y = A(-3)' + B(-2)* O y = A sin(-3t) + B cos(-2t) O y = -3eAt 2e Bt O y = Ae 3t + Be 2t
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