The same torque is applied to two tubes with identical metal sheets, determine the ratio of Teirle/T. square of the shear stresses. Given: r = 19 mm, S = 22 mm, and t = 2.04 mm. S. S
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- The solid steel rod (1) has an allowable shear stress of 12 ksi. The brass tube (2) has an allowable shear stress of 5 ksi. The diameter of the rod is d1 = 0.625 in. The outside diameter of the tube is D2 = 1.625 in., and its wall thickness is t2 = 0.125 in. The tube is attached to a fixed plate at C, and both the rod and the tube are welded to a rigid end plate at B. Determine the largest torque Tmax that can be applied at the upper end of the steel rod.A torque of 2 kip # in. is applied to the tube. If the wall thickness is 0.1 in., determine the average shear stress in the tube.A 40-mm diameter hole is drilled 3-m deep into the steel shaft. When the first torque is removed at point B with 6000-N-m and the second torque is applied at point C with 2000-N-m, determine the following:a) The Maximum Shear Stress in the shaft.b) The angle of rotation of the free end of the shaft.
- The shaft consists of three concentric tubes, each made from the same material and having inner and outer radii as given below. Length of shaft is 2m. One end is fixed to the wall and to the other end a disc is attached. If a torque of T =800 N.m is applied at the disc end, determine the maximum shear stress in the shaft. 1. Inner tube: r; = 20mm, r, = 25 mm 2. Center tube: r; = 26 mm, r. = 30 mm 3. Outer tube: r = 32mm, r, = 38mmA steel shaft of 50 mm diameter and 500 mm length has a total angle of twist of 0.5. If the Modulus of Rigidity is taken as 79 GPa, determine the maximum allowable shear stress that can be induced in the shaftA 3-m aluminum tube with the cross section shown carries a 200 N-m torque. Determine the following:a) the Maximum Shear Stress in the tubeb) The relative angle of rotation of the ends of the tube. (For aluminum, use G = 28GPa)
- The wrench is applied to two forces each of magnitude P. The steel shaft AB has a diameter of 15 mm. If the shear stress in the shaft is not exceed 120 MPa and the angle of twist is not exceed 5; find the largest allowable of P. For steel; use G = 80 GPa.The solid-circular member AC, having a diameter D and a shear modulus of 69 GPa, is subjected to the torques 2T and 3T at points A and B, respectively. If tallow = 35 MPa and (fA/C)allow =2o, determine the maximum permissible value of the torque T. Use the table given below and your student ID to find the values of L1, L2, and D. Student ID L1 (m) L2 (m) D (mm) 1131731 1 0.6 78If the permissible shear stress of a solid shaft is of 70MPa, the torque angle between two cross sections separated 2.5m does not exceed 3°, the applied torque is of 1400N.m and G=11Gpa a. Determine the required diameter in function of the shear stress b. Determine the required diameter in function of the angle of twist
- A bar having a radius equal to 0.375 inches is subjected to different torques along its span as shown below. Determine the max shear stress that is experienced by the bar.The copper pipe [G = 7,000 ksi] has an outside diameter of 3.875 in. and a wall thickness of 0.250 in. The pipe is subjected to a uniformly distributed torque of t = 80 lb-ft/ft along its entire length. Using a = 2.5 ft, b = 4.0 ft, and c = 8.5 ft, determine(a) the maximum shear stress in the pipe.(b) the rotation angle φC at the free end of the shaft.A solid bar having a diameter of 160 mm is to be replaced by a rectangular tube having cross-sectional area of 150 mm x 310 mm to the median line of the cross-section. (a) Determine the required thickness of the tube so that the maximum shear stress in the tube will not exceed the maximum shear stress in the solid bar. (b) Determine the shear stress in the tube . If it is subjected to a torque T = 15 kN-m and a thickness of 10 mm. and (c) Determine the angle of twist in degrees of the tube if the length of the tube is 1000 mm and the shear modulus is 75 GPa. Thickness of the tube is 10 mm and the torque T = 15 kN-m.