The sieve analysis data for a granular soil are given below. NES LECTUREY % passing 19 mm sieve =100 % passing 4.75 mm (4 sieve) = 61 % passing 2 mm = 45 % passing 0.075 mm (200 sieve) = 16 % passing 0.06 mm (4 sieve) = 13 % passing 0.05 mm ( sieve) = 8 % passing 0.002 mm (4 sieve) = 5 What are the percentages of gravels, sands and fines within this soil, based on the Unified Soil Classification System (USCS), AASHTO, USDA and MIT Standards? Mass Opening (mm) Sieve No. Retained (g) 4.75 4

The sieve analysis data for a granular soil are given below. NES LECTUREY % passing 19 mm sieve =100 % passing 4.75 mm (4 sieve) = 61 % passing 2 mm = 45 % passing 0.075 mm (200 sieve) = 16 % passing 0.06 mm (4 sieve) = 13 % passing 0.05 mm ( sieve) = 8 % passing 0.002 mm (4 sieve) = 5 What are the percentages of gravels, sands and fines within this soil, based on the Unified Soil Classification System (USCS), AASHTO, USDA and MIT Standards? Mass Opening (mm) Sieve No. Retained (g) 4.75 4

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter2: Soil Deposits-origin, Grain-size, And Shape

Section: Chapter Questions

Problem 2.4P: For a soil, given: D10 = 0.08 mm D30 = 0.22 mm D60 = 0.41 mm Calculate the uniformity coefficient...

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For a soil, given: D10 = 0.08 mm D30 = 0.22 mm D60 = 0.41 mm Calculate the uniformity coefficient and the coefficient of gradation of the soil. 2.4 Repeat Problem 2.3 for the following: D10 = 0.24 mm D30 = 0.82 mm D60 = 1.81 mm
Calculate the coefficient of gradation, Cc. ? Classify the soil by AASHTO and USCS system. (LL = 30, PL = 10) ? Use this given M=Mass of soil retained in pan +∑Mass reatianed in each sieve⇒M=617 gM=Mass of soil retained in pan +∑Mass reatianed in each sieve⇒M=617 g Sieve No. Opening Size (mm) Mass retained (g) %Mass retained=MiM×100=MiM×100 %Cumulative mass retained % Finer 4 4.750 28 =28617×100%=4.54%=28617×100%=4.54% 4.54 95.46 10 2.0 42 =42617×100%=6.81%=42617×100%=6.81% 11.35 88.65 20 0.850 48 =48617×100%=7.78%=48617×100%=7.78% 19.13 80.87 40 0.425 128 =128617×100%=20.74%=128617×100%=20.74% 39.87 60.13 60 0.250 221 =221617×100%=35.82%=221617×100%=35.82% 75.69 24.31 100 0.150 86 =86617×100%=13.94%=86617×100%=13.94% 89.63 10.37 200 0.075 40 =40617×100%=6.48%=40617×100%=6.48% 96.11 3.89 Pan 24 =24617×100%=3.89%=24617×100%=3.89% 100 0 Now, to plot the GSD curve, the % finer is kept on the vertical axis and the opening size are kept on the horizontal axis -…
Calculate the CEC (m.e./100g soil) using the following given miliequivalent weights obtained from a 25g soil sample (a. Ca++= 2.23 m.e; b. Mg++=1.32 m.e.; c. Na+= 1.98 m.e.; d. K+= 1.87 m.e.; e. H+= 1.27 m.e.; f. Al+++= 0.11 m.e.; g. NH4+= 2.3 m.e.; h. NO3-= 1.5 m.e.
Calculate the CEC of a 100g soil sample that was found to contain the following cations: Ca2+ = 0.12g Mg2+ = 0.024g K+ = 0.078g Al3+ = 0.027g NH4+ = 0.036g H+ = 0.002g
Calculate the coefficient of permeability in mm/s of a soil sample, 6 cm in height and 50 cm2 in cross sectional area, if a quantity of water equal to 430 ml passed down in 10 minutes, under an effective constant head of 40 cm. a.625 X 10^-2 b.5.9 x 10^-2 c.1.6 X 10^-5 d.2.15 x 10^-2
The following are the results from the liquid limit tests for a soil: Number of Blows, N Moisture Content, % 16 38.3 21 33.4 34 29.1 a) Draw the flow curve and obtain the liquid limit. b) If the Plastic Limit is determined to be 8%, what is the Plasticity Index of the soil? c) What is the Liquidity Index of the soil if the in situ w = 35%? What does this specific result tell us about this soil?
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8. a) According to the results of a sieve analysis in Table 1 below, plot the sieve analysis graph and construct a soil particle-size distribution curve. Table 1 Sieve Size (mm) Mass of retained (g) 4.75 0 2.00 40 0.850 60 0.425 89 0.250 140 0.180 122 0.150 210 0.075 56 Pan 12 b) Determine i)Effective size D10, D30, and D60 ii)Uniformity coefficient, Cu iii)Coefficient of curvature, Cc iv)Classify the soil based on the graph
The moist unit weights and degrees of saturation of a soil are given in the table. y (kN/m3) S(%) 16.62 50 17.71 75 Determine: a. e b. Gs Show handwritten solutions.
The figure shows water flowing through two saturated soils (A and B) in the hatched areas. Calculate the pressure head elevation head and total head at points X, Y and Z. Also calculate the flow rate through the soils. the cross sectional area of the sample is 15 m2
A sample of soil having a mass of 360 g is to be placed into a cylinder whose volume is 750 cm³. An additional volume of 573 cm³ of water is required to fill the container with moisture content = 22.5% and GS = 2.60. 1. Compute the bulk unit weight. a. 6.16 kN/m³ b. 16.25 kN/m³ c. 18.19 kN/m³ d. 19.95 kN/m³ 2. Compute the submerged unit weight. a. 8.17 kN/m³ b. 9.42 kN/m³ c. 10.02 kN/m³ d. 12.18 kN/m³ 3. Compute the porosity. a. 0.56 b. 0.46 c. 0.36 d. 0.26
Sketch the figure and determine coefficient of permeability (k) in mm/min using constant head permeability, given the following data, Water flows horizontally The height of the reservoir supply source is 2 m above the elevation of the outlet. The soil sample length in the direction of water flow is 200 mm. The cross-sectional area of the soil sample is 1,950 mm2. The measured volume of flow for the steadystate condition is 500 ml in a 10-minute time period.