The table below shows the lab result of the sieve analysis of a soil sample Diameter (mm) Percent Passing, % 100 4.750 2.000 0.850 94.5 86.3 0.425 74.1 0.250 54.9 0.180 38.1 0.150 9.3 0.075 1.7 a. Calculate the coefficient of gradation of the soil sample. Use logarithmic interpolation b. Classify the soil according to USCS

The table below shows the lab result of the sieve analysis of a soil sample Diameter (mm) Percent Passing, % 100 4.750 2.000 0.850 94.5 86.3 0.425 74.1 0.250 54.9 0.180 38.1 0.150 9.3 0.075 1.7 a. Calculate the coefficient of gradation of the soil sample. Use logarithmic interpolation b. Classify the soil according to USCS

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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GEOTECHNICAL ENGINEERING: The resuts of a sieve analysis for a soil sample are given in the Table. Cc = 0.5 and Cu = 5. If the LL and the PL of the soil sample are 55 and 40 respectively, classify the soil according to USCS classification. Sieve Opening (mm) % passing 4.75 45 0.075 9
The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Sieve No. Diameter Soil A 4 4.760 96 8 2.380 80 10 2.000 78 20 0.840 61 40 0.420 56 60 0.250 48 100 0.150 39 200 0.075 33 Characteristics of No. 40 Fraction LL 46 PL 31
Why is the hydrometer method commonly used to obtain data on the sizes of silt and clay particles in soil samples, and not the sieve method?
GEOTECHNICAL ENGINEERING: The resuts of a sieve analysis for an inorganic soil sample are given in the table. If the If the LL and the PL of the soil sample are 38 and 18 respectively, classify the soil according to USCS classification. Sieve Opening (mm) % passing 4.75 80 2 68 0.85 54 0.425 33 0.075 18
The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Sieve No. Diameter Soil A 4 4.760 80 8 2.380 71 10 2.000 69 20 0.840 63 40 0.420 57 60 0.250 43 100 0.150 40 200 0.075 39 LL 36 PL 21
The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Sieve No. Diameter Percent Passing 4 4.760 100 6 2.380 91 10 2.000 88 20 0.840 76 40 0.420 55 60 0.250 50 100 0.150 47 200 0.075 46 Characteristics of No. 40 Fraction LL 50 PL 34
soil mechanic. Classify the soil according to unified soil classification system USCS; if the following data is given : Passing sieve No. 200 =7% / Passing sieve No. 4 = 40% / D10= 0.18, D30= 0.69 and D60= 3/ LL-28%, Pl=19%
using tge inverse distance weighted interpolation method and the value of three known soil samples, calculate the gold concentration in the unknown point, P01. Use a power (exponentO of n=3 Samples /Au ppb / Eastings / Northings Soil 01 / 17 344937 250624 Soil 02 / 253 / 345261 / 249165 Soil 03 / 1002 / 345584 / 249137 P01 / ? 345123 / 249098 Round to the ones
40.) The given data shows a sieve analysis of a soil sample. Classify the soil using AASHTO Method. Tables are provided below. Sieve No. Diameter (mm) Percent Passing No. 4 4.760 96 No. 8 2.380 80 No. 10 2.000 78 No. 20 0.840 61 No. 40 0.420 56 No. 60 0.250 48 No. 100 0.150 39 No. 200 0.075 33 Characteristics of No. 40 Fraction LL 38 PL 29 A. A-2-4(0) B. A-1-b(0) C. A-1-a(0) D. A-3(0) E. A-2-5(0)
6. 1kg of soil sample, placed after a period of time, the moisture content from 25% to 20%, the water in the soil decreased ( ).A. 0.06kg B. 0.05kgC. 0.04kg D. 0.03kg 8. When calculating the time factor Tv, if the soil is drained on one side, H in the equation is taken as the thickness of the soil layer ( ).A. half B. double C. 2 times D. 4 times
A pycnometer test for the determination of water content of a soil sample having the Gs=2.70, yielded following data: Weight of moist soil=230.75g Weight of Pycnometer full of water=2965.20g Weight of Pycnometer+soil+water =3092.85g
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