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- l4//me shear and bending moment diagram as shown in figure. by graphical method. 132.5KN 122.5KN.m ) sgN/m b itwd L oe—dine—dA fiberglass pipe is lifted by a sling, as shown in the figure. The outerdiameter of the pipe is 6,0 in., its thickness is 0.25 in,, and its weightdensity is 0,053 1b/in3 the length of the pipe is L = 36 ft and the distancebetween lifting points is s = 11 ft.a. Determine the maximum bending stress in the pipe due to its ownweight,b. Find the spacing s between lift points which minimizes thebending stress. What is the minimum bebding stress?c. What spacing s leads to maximum bending stress? What is thatstress?A cold drawn steel rod of circular cross-section is subjected to a variable bending moment of 565 Nm to 1130 N-m as the axial load varies from 4500 N to 13 500 N. The maximum bending momentoccurs at the same instant that the axial load is maximum. Determine the required diameter of the rodfor a factor of safety 2. Neglect any stress concentration and column effect. Assume the followingvalues:Ultimate strength = 550 MPaYield strength = 470 MPaSize factor = 0.85Surface finish factor = 0.89Correction factors = 1.0 for bending= 0.7 for axial load
- A simply supported beam AB = 11 m has a hollow rectangular cross-section with 11 cm as width, 28 cm as depth and inner thickness as 1 cm is subjected to a point load of 5 N & 6 N acting at C and D respectively and a uniformly distributed load (UDL) of 9 N/m starts from mid-span and ends at the right support of the beam. Determine the maximum bending stress and the bending stress at 1 cm from the top. Take AC = 1 m & CD = 1 m. iv) Maximum Bending Moment (Please write the Maximum bending moment valve in "Nm") = v) Moment of Inertia, I = vi) Maximum bending stress = vii) Bending stress at 1 cm from the top =A simply supported beam AB = 9 m has a hollow rectangular cross-section with 13 cm as width, 20 cm as depth and inner thickness as 1 cm is subjected to a point load of 8 N & 8 N acting at C and D respectively and a uniformly distributed load (UDL) of 9 N/m starts from mid-span and ends at the right support of the beam. Determine the maximum bending stress and the bending stress at 1 cm from the top. Take AC = 1 m & CD = 2 m. i) Reaction force at B in (N)= ii) Reaction Force at A in(N)= iii) The distance from B at which the shear Force value changes from "-" to "+" in (m)= iv) Maximum Bending Moment (Please write the Maximum bending moment valve in "Nm") = v) Moment of Inertia, I in (m^4)= vi) Maximum bending stress in (N/m^2)= vii) Bending stress at 1 cm from the top in (N/m^2) =Since the bending safety stress em = 10 MPa, shear safety stress em = 600 kPa of the rectangular section beam given in the figure and whose width is b = 150 mm, the height of the beam section h is at least how much is the height of the beam section in order not to exceed the safety stress values. should be.
- Rectangular section and width given in the figureThe bending safety stress of the beam with b = 150 mm em = 10 MPa,Since shear safety stress em = 600 kPa,In order that the stresses that will occur do not exceed the safety stress valuesWhat should be the minimum height h of the beam section.A simply supported beam AB = 10 m has a hollow rectangular cross-section with 17 cm as width, 28 cm as depth and inner thickness as 2 cm is subjected to a point load of 7 N & 5 N acting at C and D respectively and a uniformly distributed load (UDL) of 8 N/m starts from mid-span and ends at the right support of the beam. Determine the maximum bending stress and the bending stress at 2 cm from the top. Take AC = 2 m & CD = 2 m. i) Reaction force at B in (N)= 33.4N ii) Reaction Force at A in (N) = 18.6N iii) The distance from B at which the shear Force value changes from "-" to "+" in (m) = 4,175m find the ; iv) Maximum Bending Moment (Please write the Maximum bending moment valve in (Nm) = v) Moment of Inertia, I in (m^4)= vi) Maximum bending stress in (N/m^2)= vii) Bending stress at 2 cm from the top in (N/m^2) =A simply supported beam AB = 11 m has a hollow rectangular cross-section with 18 cm as width, 27 cm as depth and thickness as 1 cm is subjected to a point load of 5 N & 5 N acting at C and D respectively and a uniformly distributed load (UDL) of 7 N/m starts from mid-span and ends at the right support of the beam. Determine the maximum bending stress and the bending stress at 1 cm from the top. Take AC = 1 m & CD = 1 m. Solution: i) Reaction force at B = ________N ii) Reaction Force at A = ________N iii) The distance from B at which the shear Force value changes from "-" to "+" = ________m iv) Maximum Bending Moment (Please write the Maximum bending moment valve in "Nm") = ________Nm v) Moment of Inertia, I = ________m^4 vi) Maximum bending stress = ________N/m^2 vii) Bending stress at 1 cm from the top = ________N/m^2
- A hollow steel box beam has the rectangularcross section shown in the figure. Determinethe maximum allowable shear force V that may acton the beam if the allowable shear stress is 36 MPa.Beam cross section is shown below. If a resultant shear force, V acting at the beam cross section is 40 kN, (a) Determine the shear stress due to bending at points C (b) Sketch the shear stress distribution over the beam cross section and describe the shear stress pattern at the interface between flange and web. Given I NA = 301.3 x 10-6 m4A shaft is made of a polymer having an elliptical cross section. If it resists an internal moment of M = 50 N # m, determine the maximum bending stress in the material (a) using the flexure formula, where Iz = 1 4 p(0.08 m)(0.04 m)3, (b) using integration. Sketch a three-dimensional view of the stress distribution acting over the cross-sectional area. Here Ix = 1 4 p(0.08 m)(0.04 m)3.