The specific rotation of compound X is +10.2°. A mixture of compound X and its enantiomer are placed in the polarimeter and the observed rotation is +2.3°. Find the enantiomeric excess and determine which enantiomer is in excess (+ or -).
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- A pure sample of the R isomer of a particular compound is known to have a specific rotation of -40. A mixture of the two enantiomers of the compound gives a specific rotation of +8. What are the percentages of the S and R enantiomers in the mixture?If the sample of the pure R enantiomer of a molecule has a specific rotation of -40 degrees and your mixture of that molecule has an 82% ee S, what is the observed specific rotation of your sample?A 0.26 M solution of an enantiomerically pure chiral compound D has an observed rotation of +0.197° in a 1‑dm sample container. The molar mass of the compound is 132.3 g/mol. a. What is the specific rotation of D? b. What is the observed rotation if this solution is mixed with an equal volume of a solution that is 0.26 M in L, the enantiomer of D? c. What is the observed rotation if the solution of D is diluted with an equal volume of solvent?
- which is true if a mixture of enantiomer with a specific rotation of +2 if specific rotation of pure(r) enantiomer is +80? 1. almost racemic mixture 2. mixture contains 100% enantiomeric excess of (r) 3. (s)>(r) 4. (s)<(r)2. A mixture of two enantiomers has as observed rotation of -18°. The specific rotation of the (-)enantiomers is -27°. Find the % of the two enantiomers in the solution.A solution prepared by mixing 10 mL of a 0.10 M solution of the R enantiomer of a compound and 30 mL of a 0.10 M solution of the S enantiomer was found to have an observed specific rotation of +4.8. What isthe specific rotation of each of the enantiomers? (Hint: mL * M = millimole, abbreviated as mmol)
- An attempt at synthesizing a certain optically-active compound resulted in a mixture of its enantiomers. The mixture had an observed specific rotation of +11.5°+11.5°. If it is known that the specific rotation of the ?R enantiomer is −38.0°−38.0°, determine the percentage of each isomer in the mixture.If the optical rotation of a pure enantiomer A is +10 and the optical rotation of a mixture of two enantiomers (A+B) is -4 (Negative 6), what is the percentage of A and B in that mixture?You synthesize the enantiomer of levetiracetam, but your specific rotation is found to be 67.8. What is the enantiomeric excess (% ee) of this product?
- The [α] of a pure enantiomer is -39°. The observed rotation of a sample containing both enantiomers was found to be -0.62°. a) Calculate the enantiomeric excess (e.e %) b) Calculate the percent of each enantiomer present.Identify pairs of molecules that represent enantiomers and diastereomers and identify each center stereogenic by writing R or S next to it.(+)-Tartaric acid has a specific rotation of +12.0°. Calculate the specific rotation of a mixture of 68% (+)@tartaric acid and 32% (-)@tartaric acid