The speed of the 103.75 g particle is 1047.41 cm/s as it passes the 0 = 34.25° position shown. The coefficient of kinetic friction between the particle and the vertical plane track is 0.24. If the radius of curvature of the track is 4.84 m, determine the magnitude (m/s²) of the deceleration of the particle. 4.84 m Technology Driven by (nnovntion FRUALARAN FEU DILIMAN FRU TECH

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter5: More Applications Of Newton’s Laws
Section: Chapter Questions
Problem 35P
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The speed of the 103.75 g particle is 1047.41 cm/s as it
passes the 0 = 34.25° position shown. The coefficient of
kinetic friction between the particle and the vertical plane
track is 0.24. If the radius of curvature of the track is 4.84
m, determine the magnitude (m/s2) of the deceleration of
the particle.
4.84 m
Technology Driven by (nnovation
PEU ALARANG RU DLIMAN PRU TECH
Transcribed Image Text:The speed of the 103.75 g particle is 1047.41 cm/s as it passes the 0 = 34.25° position shown. The coefficient of kinetic friction between the particle and the vertical plane track is 0.24. If the radius of curvature of the track is 4.84 m, determine the magnitude (m/s2) of the deceleration of the particle. 4.84 m Technology Driven by (nnovation PEU ALARANG RU DLIMAN PRU TECH
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