The spring of modulus k = 870 N/m is stretched a distance ō = 71 mm when the mechanism is in the position shown. (a) Calculate the force Pmin required to initiate rotation about the hinge axis BC, and determine the corresponding magnitudes of t bearing forces which are perpendicular to BC. (b) What is the normal reaction force at Dif P = Pmin/2? 95 mm 55 mm C 146 mm k = 870 N/m 49 mm 173 mm B 49 mm 55 mm 129 mm 46 mm
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- The structure consists of a spring CD and a solid member ABC with a slot at B. The peg at B fits loosely into the slot at B and can hence be interpreted as a smooth support. The unstretched length of the spring is 80 mm. 50 mm 150 mm 50 mm A D C B k = 600 N/m 1.1 Draw separate free-body diagrams of member ABC and the spring CD. 1.2 Comment on the existence of two-force members and three-force members in this system. 1.3 Determine the reactions at A and B on the member ABCThe jib crane is designed for a maximum capacity of 14 kN, and its uniform I-beam has a mass of 270 kg. Plot the magnitude R of the force on the pin at A as a function of x through its operating range of x = 0.2 m to x = 4.0 m. On the same set of axes, plot the x- and y-components of the pin reaction at A. Do these plots on a separate piece of paper. Then answer the following questions in Wiley Plus as a check for your work. (You can disregard the plot, I only need a, b, c, and d)The jib crane is designed for a maximum capacity of 7 kN, and its uniform I-beam has a mass of 160 kg. Plot the magnitude R of the force on the pin at A as a function of x through its operating range of x = 0.2 m to x = 3.6 m. On the same set of axes, plot the x- and y-components of the pin reaction at A. Do these plots on a separate piece of paper. Then answer the following questions in Wiley Plus as a check for your work.(a) What is the value of R when x = 0.9 m?(b) What is the value of R when x = 3.1 m?(c) Determine the minimum value of R and the corresponding value of x.(d) For what value of R should the pin at A be designed?
- Determine the magnitude and direction of the angle theta of the force FAB that must be exerted on bar AB to maintain equilibrium of the system. The suspended mass is 110 kg. Neglect the size of the pulley at A and treat all pulleys as smooth. What should happen to maintain the equilibrium of the system if FAB acts with an angle theta= 0°?Consider g = 9.81 m/s2.A rear suspension system for a front wheel-drive vehicle is shown here. Spring EF is offset behind member CD. The normal force due to contact between the wheel and the road is 4200 N. Assume the weight of the wheel and suspension system components is negligible. Determine the magnitude of the member CD. Is the member in tension or compression? Determine the support reactions at A. Determine the unstretched length of the spring EF given a spring constant of 150 kN/m.The bar AC is supported by a joint at A and a pin B that is free to slide in the same direction (alpha) of the bar. A bar is connected at C and a force is applied in the theta direction. Consider that L1 = 2.7 m, L2 = 1.7 m, alpha = 13 °, theta = 25 °, and P = 68 kN. Determine the magnitude of the force (kN) on pin B.
- Q4: of a car غطاء محرك The i Jul. The bonnet is held open at an angle of 60° to the horizontal by a vertical force V applied at one end of the bonnet (shown on the diagram). The long, has a weight of 25 N and its center diagram shows the open bonnet bonnet is 0.90 m of gravity G is 0.35 m from the hinge at O. 1) On the diagram, draw and label the two forces other than V acting on the bonnet. By taking moments about A, Proof that the vertical 2) force V applied at the end of the bonnet is 9.7 N. 3) Calculate the magnitude of the force acting at the hinge ON.A.The bar of negligible weight is supported by two springs, each having a stiffness k = 98 N/m. If the springs are originally unstretched, and the force is vertical as shown, determine the angle the bar makes with the horizontal, when the 31-N force is applied to the bar. B.Determine the stiffness k of each spring so that the 32-N force causes the bar to tip = 13.6° when the force is applied. Originally the bar is horizontal and the springs are unstretched. Neglect the weight of the bar.Determine the additional mass required for stable equilibrium. Meter stick: xcm = 50.0 cm, m = 150.0 g. Hanger clamp: x = +0.0 cm, m = 16.5 g. (see the figure below)
- A sign of weight 2280 N is supported as shown by a ball and socket support at A and two cables BC and AD 1- Tension in cable BC is (N) : (a. 4560 - b. 6840 - c. 5700 - d. 7980 - e. 9120 ) 2- Tension in cable AD is (N): (a. 10260 - b. 13680 - c. 15960 - d. 18240 - e. 10640 ) 3-Magnitude of x-component of reaction at O is (N): (a. 5700 - b. 6840 - c. 7980 - d. 9120 - e. 10260 ) 4- Find Magnitude of y-component of reaction at O is (N) 5- Find Magnitude of z-component of reaction at O is (N)The quadriceps tendon attaches to the tibia at a 30° angle 4 cm from the joint center at the knee. When an 80 N weight is attached to the ankle 28 cm from the knee joint, how much force is required of the quadriceps to maintain the leg in a horizontal position? When the subject mass is 75 kg, what is the magnitude and direction of the reaction force exerted by the femur on the tibia? (Utilize “Foot and leg” in the included chart to obtain weight of the lower leg and location of COM. Neglect the action of other muscles.)in the system shown, the bar AB can withstand a tension of 4.90 kN, and a compression of 2.53 kN; the spring constant k is 2.85 kN / m, the spring's undeformed length is 0.433 m, the mass of W is 365 kg, and the force P makes an angle of 60 ° with the horizontal. Calculate the stretched length of the spring and the magnitude of the force P so that:- The bar fails due to tension- The bar fails due to compression NOTE 1: For the direction of the force P do not be guided by the drawing. The force P can point in any direction (all 4 quadrants) as long as it maintains the indicated angle with respect to the horizontal.