The standard enthalpy change for the following reaction is -851 kJ at 298 K. 2 Na(s) + O2(g) + H2(g) ---> 2 NaOH(s)   ΔH° = -851 kj What is the standard enthalpy change for this reaction at 298 K?   Na(s) + 1/2 O2(g) + 1/2 H2(g)  NaOH(s)

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