The standard molar enthalpy change AH°= -3135 kJ for the combustion of benzene. CH(1)+15/2 0,2(9) →6 CO,(g)+3 H,0(g) AHº= -3135 kJ Calculate the standard molar enthalpy of formation for benzene AH°F[CH,(1)] based on the following standard enthalpies of formation: AH°ƒ[C0,(g)] = -393.5 kJ/mol and AH°F[H,0(g)] =-241.8 kJ/mol. %3D Select one: a. -7670 kJ/mol b. -3230 kJ/mol C. -783 kJ/mol d. +49 kJ/mol Next pac Previous page

Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section5.7: Enthalpy Calculations
Problem 5.10CYU: Calculate the standard enthalpy of combustion for benzene, C6H6. C6H6() + 15/2 O2(g) 6 CO2(g) + 3...
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The standard molar enthalpy change AH°= -3135 kJ for the combustion of benzene.
CH(1)+15/2 O2{9) → 6 CO,(g)+3 H,0(g) AH°= -3135 kJ
Calculate the standard molar enthalpy of formation for benzene AH°F[CH 0)] based on the
following standard enthalpies of formation: AH°f[CO,(g)] = -393.5 kJ/mol and AH°F[H,0(g)]
=-241.8 kJ/mol.
Select one:
a. -7670 kJ/mol
b. -3230 kJ/mol
C 783 kJ/mol
d. +49 kJ/mol
Next pac
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Transcribed Image Text:The standard molar enthalpy change AH°= -3135 kJ for the combustion of benzene. CH(1)+15/2 O2{9) → 6 CO,(g)+3 H,0(g) AH°= -3135 kJ Calculate the standard molar enthalpy of formation for benzene AH°F[CH 0)] based on the following standard enthalpies of formation: AH°f[CO,(g)] = -393.5 kJ/mol and AH°F[H,0(g)] =-241.8 kJ/mol. Select one: a. -7670 kJ/mol b. -3230 kJ/mol C 783 kJ/mol d. +49 kJ/mol Next pac Previous page
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