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OOPs
In today's technology-driven world, computer programming skills are in high demand. The object-oriented programming (OOP) approach is very much useful while designing and maintaining software programs. Object-oriented programming (OOP) is a basic programming paradigm that almost every developer has used at some stage in their career.
Constructor
The easiest way to think of a constructor in object-oriented programming (OOP) languages is:
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- Java Program ASAP Here is a FileSorting program to read a CSV file, sorts a list of integers on each row, and prints a comma separated list of sorted integers on the console. Modify ir by removing or changing the main method os it passes all the test cases. import java.io.File;import java.io.FileNotFoundException;import java.util.ArrayList;import java.util.Scanner; public class FileSorting { private static final String FILENAME = "somefile.txt"; public static void main(String[] args) { // read integers from input file Scanner fileReader; ArrayList<Integer> numbers = new ArrayList<>(); try { fileReader = new Scanner(new File(FILENAME)); while(fileReader.hasNextLine()) { numbers.add(Integer.parseInt(fileReader.nextLine().trim())); } fileReader.close(); }catch(FileNotFoundException fnfe){ System.out.println("File " + FILENAME + " is not…09.Write a program that reads in a set of coin descriptions from a file. The input file has the format coinName1 coinValue1 coinName2 coinValue2 ...Add a method void read(Scanner in) throws FileNotFoundException to the Coin class of Section 7.2. Throw an exception if the current line is not properly formatted. Then implement a method static ArrayList<Coin> readFile(String filename) throws FileNotFoundException In the main method, call readFile. If an exception is thrown, give the user a chance to select another file. If you read all coins successfully, print the total value.Create a java method that reads from a text file and returns/makes a ragged array of doubles. The maximum rows is 10 and the maximum columns for each row is 10. Each row in the file is separated by a new line. Each element in the row is separated by a space. The method signature is such: public static double[][] readFile(File f)
- write a program that reads the students.txt file and stores the name of the student and the grade information as a student object in an arraylist sorts the students names based on their first grade in decreasing order using the selection sort algorithm writes the sorted list as the students last name , middle name (if theres one), first name , and grade information into a text file output example: Robison, Lee 95 80 Green, Alex R 85 60 Waston, Zoe G 100 80 use javaWe know that the first file name is stored at index zero in the ArrayList, and the list stores the file names as strings, so could we write the body of listAllFiles along the following lines? System.out.println(files.get(0)); System.out.println(files.get(1)); System.out.println(files.get(2)); etc. How many println statements would be required to complete the method?Code isn't running, how do i get it to print to a txt file public class WeightedAvgDataAnalyzer { public static void description() {System.out.println("This program calculates the weighted average of "+ "all those numbers except the lowest n numbers. \n");}//end// get numbers from userpublic static ArrayList<Double> getNumbers(Scanner en) {ArrayList<Double> list = new ArrayList(); while(en.hasNextDouble()) {list.add(en.nextDouble());}return list;}//end//gets the lowest number from user and return it as npublic static int getNumberLowest(Scanner scan) {int n = scan.nextInt();return n;}//end//get the weightpublic static double getWeight(Scanner en) {double weight = en.nextDouble();return weight;}//end //remove Lowest And CalAvg -- returns the avgragepublic static double calculateWeightedAverage(ArrayList<Double> list, int lowest) {double first = list.get(0);double sec = list.get(0);for (double n : list) {if (first > n) {sec = first;first = n;} else if (sec…
- public class ShoppingListDriver{ public static void main(String[] args){ ShoppingList sl=new ShoppingList(3);sl.insert(null);sl.insert(new Item("Bread", "Carb Food", 2, 2.99));sl.insert(new Item("Seafood","Sea Food", -1, 10.99));sl.insert(new Item("Rice", "Carb Food",2, 19.99));sl.insert(new Item("Salad Dressings","Dessing", 2, 19.99));sl.insert(new Item("Eggs", "Protein",2, 3.99));sl.insert(new Item("Cheese","Protein", 2, 1.59));sl.insert(new Item("Eggs", "Protein",3, 3.99));sl.printNames();sl.print(); System.out.println("After removing Eggs:");sl.remove(new Item("Eggs","Protein",0,0));sl.printNames();sl.print(); }}I need to store data from a text file into an object array then store the object array into a linked list using Java Example of file im trying to convert: //String //Int //Double //Double //Int Joe 101 17.2 10.0 4 Alex 97 15.3 12.5 7 Maria 85 16.4 18.2 9 Steve 153 23.5 16.3 8Write a method public static intreadInFile(String line, File file) that returns the position numberof a line in the file filename or −1 if there is no such line or file.We assume that this file contains names of people with a name per line.Names (and hence lines) are listed in ascending alphabetical order in the file.We can not find the same line twice.
- Scanner sc = new Scanner(System.in);ArrayList <Student> students = new ArrayList<Student>();ArrayList <Student> courses = new ArrayList<Student>();// Method to read the file contents and stores it in// instance arraysvoid readStudents(){// Scanner class object declaredScanner readStuF = null;// try block beginstry{// Opens the file for readingreadStuF = new Scanner(new File("student.txt"));// Loops till end of the file to read recordswhile(readStuF.hasNextLine()){ String stu = readStuF.nextLine();String []eachStu = stu.split(" ");students.add(new Student(eachStu[0], eachStu[1],eachStu[2], Long.parseLong(eachStu[3]),Integer.parseInt(eachStu[4]), Integer.parseInt(eachStu[5]),Integer.parseInt(eachStu[6])));}// End of while loop }// End of try block// Catch block to handle file not found exceptioncatch(FileNotFoundException fe){System.out.println("\n ERROR: Unable to open the file for reading.");}// End of catch block // Close the filereadStuF.close();}// End of…Assume Student and GradeBook classes are defined as follows: public class Student { int id; double testsMarks[]; public double getAverage(){ double sum = 0; for(double marks : testsMarks) { sum+=marks; } return sum/testsMarks.length; } } import java.util.ArrayList; public class GradeBook { String subject; ArrayList<Student> students; public Student getStudentWithMinAverage(){ } } Define the body of getStudentWithMinAverage method that shall return the student object from students ArrayList who got minimum average marks in the class. (Please write minimum code and make use of provided code, making no change in classes' structure)I need help with my code Ask the user for a filename. Display the oldest car for every manufacturer from that file. If two cars have the same year, compare based on the VIN. here is my code so far import java.io.File;import java.io.FileNotFoundException;import java.util.ArrayList;import java.util.Scanner;class Car {String manufacturer;String model;int year;String vin;public Car(String manufacturer, String model, int year, String vin) {this.manufacturer = manufacturer;this.model = model;this.year = year;this.vin = vin;}public String getManufacturer() {return manufacturer;}public void setManufacturer(String manufacturer) {this.manufacturer = manufacturer;}public String getModel() {return model;}public void setModel(String model) {this.model = model;}public int getYear() {return year;}public void setYear(int year) {this.year = year;}public String getVin() {return vin;}public void setVin(String vin) {this.vin = vin;}}public class Demo {public static void main(String[] args)…