The smallest level of significance, at which H0H0 may be rejected is: α=0.005α=0.005α=0.01α=0.01α=0.025α=0.025α=0.05α=0.05α=0.1α=0.1H0H0 cannot be rejected at any of the above levels of significance Please answer accordingly and a like is guarunteed. A cross-sectional study is conducted to investigate cardiovascular disease (CVD) risk factors among a sample of patients seeking medical care at one ofthree local hospitals. A total of 800 patients are enrolled. Based on the following data, we would like to determine if there is a significant associationbetween the family history of CVD and the enrollment site.Enrollment SiteFamily History of CVDHospital 1Hospital 2Hospital 3TotalYes4252106200No162111327600Total204163433800Given:The value of the test statistic is x? = 6.321.Use a = 0.1 as the level of significance. The superintendent of Hospital 2 performed the Goodness of Fit Test to test whether 25% of the patients go to Hospital 1, 20% of the patients go toHospital 2 and 55% of the patients go to Hospital 3.Given: The superintendent found that the p-value for the test is 0.88355.Let:Pi = be the proportion of patients at Hospital iP2 = be the proportion of patients at Hospital 2P3 = be the proportion of patients at Hospital 3Give the null hypothesis:O Ho : Pi = P2 = P3 = 0.333О Но : р1 — р2 — Рз — 0.5o Ho : P1 + P2 + P3O Ho : P1 = P2 = P3 = 1o Ho : P1 = P2 = P3О Но : Рі 70.25, рэ 7 0.2, рз #0.55O Ho : P1 =0.25, р2 — 0.2, рз — 0.55О Но : рі — Рә — Рз — 0Calculate the value of the test statistic.Round your answer to 4 decimal places.

The given p-value for the test is 0.88355.

The superintendent of Hospital 2 performed the Goodness of Fit Test to test whether 25% of the patients go to Hospital 1, 20% of the patients go to Hospital 2 and 55% of the patients go to Hospital 3. Given: The superintendent found that the p-value for the test is 0.88355. Let: Pi = be the proportion of patients at Hospital 1 P2 = be the proportion of patients at Hospital 2 P3 = be the proportion of patients at Hospital 3 Give the null hypothesis: O Ho : Pi = P2 = P3 = 0.333 O Ho : P1 = P2 = p3 = 0.5 O Ho : P1 # P2 P3 O Ho : P1 = P2 = P3 = 1 o Ho : P1 = P2 = P3 о Но : рі + 0.25, р2 + 0.2, рз # 0.55 О Но : Рі — 0.25, р2 — 0.2, рз — 0.55 O Ho: P1 =P2 = P3 = 0 Calculate the value of the test statistic. Round your answer to 4 decimal places.

The superintendent of Hospital 2 performed the Goodness of Fit Test to test whether 25% of the patients go to Hospital 1, 20% of the patients go to Hospital 2 and 55% of the patients go to Hospital 3. Given: The superintendent found that the p-value for the test is 0.88355. Let: Pi = be the proportion of patients at Hospital 1 P2 = be the proportion of patients at Hospital 2 P3 = be the proportion of patients at Hospital 3 Give the null hypothesis: O Ho : Pi = P2 = P3 = 0.333 O Ho : P1 = P2 = p3 = 0.5 O Ho : P1 # P2 P3 O Ho : P1 = P2 = P3 = 1 o Ho : P1 = P2 = P3 о Но : рі + 0.25, р2 + 0.2, рз # 0.55 О Но : Рі — 0.25, р2 — 0.2, рз — 0.55 O Ho: P1 =P2 = P3 = 0 Calculate the value of the test statistic. Round your answer to 4 decimal places.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.6: Summarizing Categorical Data

Problem 10CYU

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