The surface area of a sphere increases at a rate of 64 n2/sec. Then the rate at which the radius changes, whenthe radius is 3 m is3.40 m/sec1.36 m/sec1.13 m/sec0.85 m/secO 1.70 m/secA27°C lt Juaủohp

Given rate of increase in the surface of sphere=64m2/sec And radius of sphere=3m Now we have to find…

Answered: The surface area of a sphere increases…

Algebra: Structure And Method, Book 1

(REV)00th Edition

ISBN:9780395977224

Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Chapter2: Working With Real Numbers

Section2.3: Rules For Addition

Problem 14P

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The surface area of a sphere increases at a rate of 64 m2/sec. Then the rate at which the radius changes, when the radius is 3 m is 3.40 m/sec 1.36 m/sec 1.13 m/sec O 0.85 m/sec O 1.70 m/sec 27C =|lA