The time temperature transformation diagram for a hypoeutectoid steel is given below. Describe the heat treatment procedure to obtain the following phase transformation (a)Tempered martensite to ferrite+pearlite (b) Austenite to ferrite+ pearlite +50% bainite. 2022707 Temperature (°C) 800 700 600 500 400 300 200 A A M (start) M(50%) M(90%) A+ F - B A+P -50% 1600 1400 -1200 -1000 E Temperature (77 800 600 400

Welding: Principles and Applications (MindTap Course List)
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Author:Larry Jeffus
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Chapter26: Welding Metallurgy
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Problem 28R: How do ferrite and cementite work together to form a strong ductile steel?
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7376
time temperature transformation diagram for a hypoeutectoid steel is given below. Describe the heat treatment procedure to obtain the
following phase transformation (a)Tempered martensite to ferrite+pearlite (b) Austenite to ferrite+ pearlite +50% bainite.
202270
Temperature (°C)
800
700
600
500
400
300
200
A
A
Af(start)
M(50%)
M(90%)
A+ F
A+P
50%
1600
-1400
1200
Temperature (F)
1000 E
800
600
400
Transcribed Image Text:7376 time temperature transformation diagram for a hypoeutectoid steel is given below. Describe the heat treatment procedure to obtain the following phase transformation (a)Tempered martensite to ferrite+pearlite (b) Austenite to ferrite+ pearlite +50% bainite. 202270 Temperature (°C) 800 700 600 500 400 300 200 A A Af(start) M(50%) M(90%) A+ F A+P 50% 1600 -1400 1200 Temperature (F) 1000 E 800 600 400
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