The tomahawk-shaped instrument shown in the accompanying gure can be used to solve the trisection problem. (PQ = QR = RS, with PTR a semicircle on PR as diameter, UR perpendicular to PS.) If LAOB is the angle to be trisected, place the tomahawk on the angle so that S lies on OA, the line segment UR passes through O, and the semicircle with diameter PR is tangent to OB at T. Prove that the triangles OTQ, ORQ, and ORS are all congruent, whence ZROA is one-third of LAOB. В T R 3 S A

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter6: Circles
Section6.3: Line And Segment Relationships In The Circle
Problem 39E: The center of a circle of radius 2 in. is at a distance of 10 in. from the center of a circle of...
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The tomahawk-shaped instrument shown in the
accompanying gure can be used to solve the
trisection problem. (PQ = QR = RS, with PTR a
semicircle on PR as diameter, UR perpendicular to
PS.) If LAOB is the angle to be trisected, place the
tomahawk on the angle so that S lies on OA, the line
segment UR passes through O, and the semicircle
with diameter PR is tangent to OB at T. Prove that
the triangles OTQ, ORQ, and ORS are all congruent,
whence ZROA is one-third of LAOB.
В
T
R
3
S
A
Transcribed Image Text:The tomahawk-shaped instrument shown in the accompanying gure can be used to solve the trisection problem. (PQ = QR = RS, with PTR a semicircle on PR as diameter, UR perpendicular to PS.) If LAOB is the angle to be trisected, place the tomahawk on the angle so that S lies on OA, the line segment UR passes through O, and the semicircle with diameter PR is tangent to OB at T. Prove that the triangles OTQ, ORQ, and ORS are all congruent, whence ZROA is one-third of LAOB. В T R 3 S A
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