The transfer function H(f ) = Vout/Vin of a filter is shown in figure below. The input signal is given by Vin(t) = 4 + 4 cos(6000 nt + 45°) Find an expression (as a function of time) for the steady-state output of the filter. H(f) |H()| 6 8 f (kHz) 3 30° 2 60° 1 90° f 2 4 8 (kHz) = 8 + 10 cos(2000 nt – 90°) Vout(t) O vout(t) O vour(t) O vout(t) = 8 cos(6000 nt + 135°) = 4 + 8 cos(3000 t) 12 + 10 cos(6000 nt + 90°) N-......

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The transfer function H(f ) = Vout/Vin of a filter is shown in figure below. The input signal is given by
Vin(t) = 4 + 4 cos(6000 t + 45°)
Find an expression (as a function of time) for the steady-state output of the filter.
|H(AI
4
6.
(kHz)
30°
60°
1
90°
2
4
6.
8
(kHz)
Vout(t) = 8 + 10 cos(2000 t – 90°)
Vout(t)
= 8 cos(6000 Tt + 135°)
Vout(t)
4 + 8 cos(3000 nt)
Vout(t)
12 + 10 cos(6000 tt + 90°)
Transcribed Image Text:The transfer function H(f ) = Vout/Vin of a filter is shown in figure below. The input signal is given by Vin(t) = 4 + 4 cos(6000 t + 45°) Find an expression (as a function of time) for the steady-state output of the filter. |H(AI 4 6. (kHz) 30° 60° 1 90° 2 4 6. 8 (kHz) Vout(t) = 8 + 10 cos(2000 t – 90°) Vout(t) = 8 cos(6000 Tt + 135°) Vout(t) 4 + 8 cos(3000 nt) Vout(t) 12 + 10 cos(6000 tt + 90°)
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