ion 5 e circuit diagram below shows a low pass RC filter circuit, the function of which is to produce a potenti ference at the output terminals (v) that resembles the potential difference at the input terminals (vn t with any high frequency elements (e.g. noise) attenuated. R Vi C e value of v is governed by the ODE dv RC +v= Vin dt ven that (in Sl units) R = 10°, C = 10-7, vin = sin(t) and v(0) = 0, use Laplace transforms to solve the ODE to find v as a function of t,

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Author:Robert L. Boylestad
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Question 5
The circuit diagram below shows a low pass RC filter circuit, the function of which is to produce a potential
difference at the output terminals (v) that resembles the potential difference at the input terminals (vin),
but with any high frequency elements (e.g. noise) attenuated.
R
23
The value of v is governed by the ODE
dv
RC-+v= Vin
dt
Given that (in SI units) R = 10°, C = 10-7, vin = sin(t) and v(0) = 0,
a)
use Laplace transforms to solve the ODE to find v as a function of t,
Transcribed Image Text:Question 5 The circuit diagram below shows a low pass RC filter circuit, the function of which is to produce a potential difference at the output terminals (v) that resembles the potential difference at the input terminals (vin), but with any high frequency elements (e.g. noise) attenuated. R 23 The value of v is governed by the ODE dv RC-+v= Vin dt Given that (in SI units) R = 10°, C = 10-7, vin = sin(t) and v(0) = 0, a) use Laplace transforms to solve the ODE to find v as a function of t,
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