The truss structure shown in Figure 3.31 is to be analyzed to find the member forces. Choosing the following determinate base structurewe calculate the member forces for load cases 0, 1, and 2.(two redundants cb and cf) 2 kips4 kips2 kipsb.fta3 kipsftftA (diagonals)= 4 inA (others)= 16 in?E (wood)= 1700 ksiFigure 3.31 Example for truss.4 kips2 kips2 kips0.0d0.03Soa3 kipsCase 0: Determinate base structure with member forces.b.0.0f0.00.00.0Case 1: Unit load at redundant 1, determinate base structure.0.00.00.0a0.0Case 2: Unit load at redundant 2, determinate base structure.

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The truss structure shown in Figure 3.31 is to be analyzed to find the member forces. Choosing the following determinate base structure we calculate the member forces for load cases 0, 1, and 2. (two redundants cb and cf)

The truss structure shown in Figure 3.31 is to be analyzed to find the member forces. Choosing the following determinate base structure we calculate the member forces for load cases 0, 1, and 2. (two redundants cb and cf)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Loads and Reactive Forces

Loads are the external influences that a beam experiences under its working conditions. For instance, a beam may be subjected to shear loads, twisting loads, bending moment, and axial loads during its working conditions. Engineers primarily deal with beams and trusses in the civil engineering domain. Due to the influence of loads, it is very crucial to determine the induced stresses and deformation values. These values give an insight into the critical area of the beam that needs to be worked upon to make it fail-safe.

Question

The truss structure shown in Figure 3.31 is to be analyzed to find the member forces. Choosing the following determinate base structure

we calculate the member forces for load cases 0, 1, and 2.

(two redundants cb and cf)

2 kips
4 kips
2 kips
b.
ft
a
3 kips
ft
ft
A (diagonals)= 4 in
A (others)= 16 in?
E (wood)= 1700 ksi
Figure 3.31 Example for truss.
4 kips
2 kips
2 kips
0.0
d
0.0
3
So
a
3 kips
Case 0: Determinate base structure with member forces.
b.
0.0
f
0.0
0.0
0.0
Case 1: Unit load at redundant 1, determinate base structure.
0.0
0.0
0.0
a
0.0
Case 2: Unit load at redundant 2, determinate base structure.

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