The two blocks A and B have weights WA= 79 lb and WB = 12 lb. (Figure 1) If the kinetic coefficient of friction between the incline and block A is μk = 0.2, determine the speed of A after it moves 3 ft down the plane starting from rest. Neglect the mass of the cord and pulleys
The two blocks A and B have weights WA= 79 lb and WB = 12 lb. (Figure 1) If the kinetic coefficient of friction between the incline and block A is μk = 0.2, determine the speed of A after it moves 3 ft down the plane starting from rest. Neglect the mass of the cord and pulleys
Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Kreith, Frank; Manglik, Raj M.
Chapter11: Heat Transfer By Radiation
Section: Chapter Questions
Problem 11.4P
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The two blocks A and B have weights WA= 79 lb and WB = 12 lb.
(Figure 1)
If the kinetic coefficient of friction between the incline and block A is μk = 0.2, determine the speed of A after it moves 3 ft down the plane starting from rest. Neglect the mass of the cord and pulleys.
Express your answer to three significant figures and include the appropriate units.
View Available Hint(s)for Part A
Hint 1for Part A. How to approach the problem
Use the principle of work and energy for the system of two blocks, which states that the system's initial kinetic energy plus the work done by all the forces acting on the two blocks as they move from their initial to their final position is equal to the system's final kinetic energy. Each block moves with its own speed, and to solve this problem, you need to find the relationship between these speeds.
Hint 2for Part A. The relationship between the speeds of the blocks
Write the equation that relates the blocks’ displacements, sAsA and sBsB, with the length of the cord. Differentiating this equation, you can express the speed of block BB, vBvB, in terms of the speed of block AA, vAvA.
The answer is not 6.07 ft/s. You may have omitted the work done by the friction force in your calculations. Recall that the friction force does negative work.
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