The unmodulated carrier is given by 110 cos(200лt), and the system operates with an index of 0.8. (a) Write the equation for m(t), the normalized sig- nal with a minimum value of −1. (b) Determine (m²(t)), the power in m„(t). (c) Determine the efficiency of the modulator. (d) Sketch the double-sided spectrum of x (t), the modulator output, giving the weights and fre- quencies of all components. 3.9 Rework Problem 3.8 for the message signal m(t) = 9 cos(20лt) + 8 cos(60лt)

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The unmodulated carrier is given by 110 cos(200лt),
and the system operates with an index of 0.8.
(a) Write the equation for m(t), the normalized sig-
nal with a minimum value of -1.
(b) Determine (m²(t)), the power in m(t).
(c) Determine the efficiency of the modulator.
(d) Sketch the double-sided spectrum of x(t), the
modulator output, giving the weights and fre-
quencies of all components.
Rework Problem 3.8 for the message signal
m(t) = 9 cos(20лt) + 8 сos(60лt)
3.9
Transcribed Image Text:The unmodulated carrier is given by 110 cos(200лt), and the system operates with an index of 0.8. (a) Write the equation for m(t), the normalized sig- nal with a minimum value of -1. (b) Determine (m²(t)), the power in m(t). (c) Determine the efficiency of the modulator. (d) Sketch the double-sided spectrum of x(t), the modulator output, giving the weights and fre- quencies of all components. Rework Problem 3.8 for the message signal m(t) = 9 cos(20лt) + 8 сos(60лt) 3.9
3.8 An AM modulator operates with the message
signal
m(t)
5
0
L
-1
m(t) = 9 cos(20лt) - 8 cos(60лt)
m(t)
Figure 3.34
T T
1
-5
T T
Det
Transcribed Image Text:3.8 An AM modulator operates with the message signal m(t) 5 0 L -1 m(t) = 9 cos(20лt) - 8 cos(60лt) m(t) Figure 3.34 T T 1 -5 T T Det
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