The answer to c is 1.58g. Please answer question on bottom. h extractionI never needne. See thelly enough.his is so sim-a test tubesolve in theottom, floater, dissolve.to be removedd more freshave the samee organic ishe theory isour organicemembered.he solubilityChapter 13).kind of a fogended drop-. Or stir theents of youron-breakingan react withclogs up theanels.he twoliquidnot enoughnt of one layerore, you maydissolve thisrial does notanalysis. You've heard thisacid, and youup, you findsome solubilities of oxalic acid as follows: 9.5 g/100 g in water; 23.7 g/100 g in etha-nol; 16.9 g/100 g in diethyl ether. Based on the solubilities, you decide to extractinto ethanol from water, forgetting for the moment that ethanol is soluble in waterand that you must have two insoluble liquids to carry out an extraction. Chagrined, youforget the ethanol and choose diethyl ether.From the preceding solubility data, we can calculate the distribution, or partitioncoefficient, for oxalic acid in the water-ether extraction. This coefficient (number)is just the ratio of solubilities of the compound you wish to extract in the two lay-ers. Here,K₁and=solubility of oxalic acid in ethersolubility of oxalic acid in waterwhich amounts to 16.9/9.5, or 1.779.Imagine that you have 40 g of oxalic acid in 1000 mL water and you put that incontact with 1000 mL ether. The oxalic acid distributes itself between the two layers. Howmuch is left in each layer? Well, if we let x g equal the amount that stays in the water,1.779x g of the acid has to walk over to the ether. And soWt of oxalic acid in ether= (1000 mL)(1.779x g/mL)=1779x gWt of oxalic acid in water = (1000 mL)(x g/mL) = 1000x gThe total weight of the acid is 40 g (now partitioned between two layers) andSOHow to Extract and Wash What2779x g = 40 gx = 0.0144Wt of oxalic acid in ether = 1779(0.0144) g = 25.6 gWt of oxalic acid in water = 1000 (0.0144) g = 14.4 gNow, let's start with the same 40 g of oxalic acid in 1000 mL of water, but thistime we will do three extractions with 300 mL of ether. The first 300-mL portion hits, and(300 mL) (1.779x g/mL)=533.7x gWt of oxalic acid in ether =Wt of oxalic acid in water = (1000 mL)(x g/mL) = 1000x gThe total weight of the acid is 40 g (now partitioned between two layers) and1533.7x g = 40 gx = 0.0261Wt of oxalic acid in ether = 533.7 (0.0261) g = 13.9 gWt of oxalic acid in water =1000 (0.0261) g = 26.1 gThat ether layer is removed, and the second jolt of 300 mL fresh ether hits, andWt of oxalic acid in ether = (300 mL)(1.779x g/mL) = 533.7x gWt of oxalic acid in water = (1000 ml)(x g/mL) = 1000x g117 C.The vapor pressure of benzaldehyde at 97 °C is about 60 mm Hg. Assumeatmospheric pressure is 760 mm Hg. If you collected 20 g of distillate from yoursteam distillation, how much of it was benzaldehyde? Show your calculation.ga(MW)APA(MW) BPB gB=Read pages 116-118 in Zubrick. The solubility of benzaldehyde is 1 g/350 mL of waterand 1 g/1 mL of ether. How much of the benzaldehyde from 3c was dissolved in the etherlayer after your first separation?

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To determine how much of the distillate collected from steam distillation is benzaldehyde, we need…

The vapor pressure of benzaldehyde at 97 °C is about 60 mm Hg. Assume atmospheric pressure is 760 mm Hg. If you collected 20 g of distillate from your steam distillation, how much of it was benzaldehyde? Show your calculation.