The variance of temperatures (Fahrenheit) in Birmingham, Ala. is 236.22. What is this variance if temp is re-expressed in Celsius? [Hint: Conversion between Fahrenheit and Celsius is a linear transformation: Fahrenheit = Celsius*1.80 + 32, or Celsius = Fahrenheit*(1/1.80) - (32/1.80)]

The variance of temperatures (Fahrenheit) in Birmingham, Ala. is 236.22. What is this variance if temp is re-expressed in Celsius? [Hint: Conversion between Fahrenheit and Celsius is a linear transformation: Fahrenheit = Celsius1.80 + 32, or Celsius = Fahrenheit(1/1.80) - (32/1.80)]

College Algebra

1st Edition

ISBN:9781938168383

Author:Jay Abramson

Publisher:Jay Abramson

Chapter4: Linear Functions

Section: Chapter Questions

Problem 8PT: Does Table 1 represent a linear function? If so, finda linear equation that models the data.

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Question

The variance of temperatures (Fahrenheit) in Birmingham, Ala. is 236.22. What is this variance if temp is re-expressed in Celsius?

[Hint: Conversion between Fahrenheit and Celsius is a linear transformation:
Fahrenheit = Celsius*1.80 + 32, or
Celsius = Fahrenheit*(1/1.80) - (32/1.80)]

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