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The voltage, V, (in volts) across a circuit is given by Ohm's law: V = IR, where / is the current (in amps) flowing through the circuit and Ris the resistance (in ohms). If we place two circuits, with resistance R and R2, in parallel, then their combined resistance, R, is 1 given by - R 1 1 Suppose the current is 3 amps and increasing at 10-2 amp/sec and R1 is 2 ohms and increasing at 0.9 R2 %3D R1 ohm/sec, while R2 is 5 ohms and decreasing at 0.3 ohm/sec. Calculate the rate at which the voltage is changing. Round your answer to three decimal places. i volts/sec

The voltage, V, (in volts) across a circuit is given by Ohm's law: V = IR, where / is the current (in amps) flowing through the circuit and Ris the resistance (in ohms). If we place two circuits, with resistance R and R2, in parallel, then their combined resistance, R, is 1 given by - R 1 1 Suppose the current is 3 amps and increasing at 10-2 amp/sec and R1 is 2 ohms and increasing at 0.9 R2 %3D R1 ohm/sec, while R2 is 5 ohms and decreasing at 0.3 ohm/sec. Calculate the rate at which the voltage is changing. Round your answer to three decimal places. i volts/sec

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 68E
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The voltage, V, (in volts) across a circuit is given by Ohm's law: V = IR, where l is the current (in amps) flowing through the circuit and Ris the resistance (in ohms). If we place two circuits, with resistance R1 and R2, in parallel, then their combined resistance, R, is 1 1. 1 given by - R Suppose the current is 3 amps and increasing at 10-2 amp/sec and R1 is 2 ohms and increasing at 0.9 R2 RI ohm/sec, while R2 is 5 ohms and decreasing at 0.3 ohm/sec. Calculate the rate at which the voltage is changing. Round your answer to three decimal places. i volts/sec
Transcribed Image Text:The voltage, V, (in volts) across a circuit is given by Ohm's law: V = IR, where l is the current (in amps) flowing through the circuit and Ris the resistance (in ohms). If we place two circuits, with resistance R1 and R2, in parallel, then their combined resistance, R, is 1 1. 1 given by - R Suppose the current is 3 amps and increasing at 10-2 amp/sec and R1 is 2 ohms and increasing at 0.9 R2 RI ohm/sec, while R2 is 5 ohms and decreasing at 0.3 ohm/sec. Calculate the rate at which the voltage is changing. Round your answer to three decimal places. i volts/sec
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