The volume of a sphere is increasing at a constant rate of 2379 cubic feet per minute. At the instant when the volume of the sphere is 891 cubic feet, what is the rate of change of the surface area of the sphere? The volume of a sphere can be found with the equation V = ar and the surface area can be found with S = 4rr2. Round your answer to three decimal places (if necessary).

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
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Author:Bruce Crauder, Benny Evans, Alan Noell
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Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
Problem 1TU: If a coffee filter is dropped, its velocity after t seconds is given by v(t)=4(10.0003t) feet per...
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The volume of a sphere is increasing at a constant rate of 2379 cubic feet per minute.
At the instant when the volume of the sphere is 891 cubic feet, what is the rate of
change of the surface area of the sphere? The volume of a sphere can be found with
the equation V = ar and the surface area ean be found with S = 4nr2. Round
your answer to three decimal places (if necessary).
Transcribed Image Text:The volume of a sphere is increasing at a constant rate of 2379 cubic feet per minute. At the instant when the volume of the sphere is 891 cubic feet, what is the rate of change of the surface area of the sphere? The volume of a sphere can be found with the equation V = ar and the surface area ean be found with S = 4nr2. Round your answer to three decimal places (if necessary).
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