The volume of a sphere is decreasing at a constant rate of 200 cubic minute. At the instant when the radius of the sphere is 2 feet, what is the rate of change of the surface area of the sphere? The feet per volume of a sphere can be found with the equation V =Tr and the surface area can be found with S = 4TT´. Round your answer to three decimal places (if necessary).

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Chapter1: Equations, Inequalities, And Mathematical Modeling
Section1.2: Linear Equations In One Variable
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The volume of a sphere is decreasing at a constant rate of 200 cubic
feet minute. At the instant when the radius of the sphere is 2 feet,
per
what is the rate of change of the surface area of the sphere? The
volume of a sphere can be found with the equation V =Tr and the
surface area can be found with S = 4Tr. Round your answer to
three decimal places (if necessary).
ft2
min
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Transcribed Image Text:Watch help video The volume of a sphere is decreasing at a constant rate of 200 cubic feet minute. At the instant when the radius of the sphere is 2 feet, per what is the rate of change of the surface area of the sphere? The volume of a sphere can be found with the equation V =Tr and the surface area can be found with S = 4Tr. Round your answer to three decimal places (if necessary). ft2 min Answer: Submit Answer attempt 1 out of 2 Priyacy Policy Terms of Service
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